I use netbeans, I try to replace \ with \\ but it fails , it can't escape the \\ character.
This is not a Netbeans issue , it's a PHP issue .
preg_replace('\','\\','text to \ be parsed');
Any sollutions?
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Alan Moore
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KB9
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3 Answers
6
Use 4 backslashes and please don't forget the delimiters:
echo echo preg_replace('~\\\\~','\\\\\\\\','text to \\ be parsed');
Explanation: When PHP parse \\\\ it will escape \\ two times, which means it becomes \\, now when PHP passes it to the regex engine, it will receive \\ which means \.
HamZa
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1@IonutFlaviusPogacian I provided an online demo with some explanation to remove all the doubts. We're talking about regex. – HamZa Aug 02 '13 at 13:22
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1Yep, good catch - it works, and the explanation now makes it clear. +1 – naththedeveloper Aug 02 '13 at 13:22
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regex is ok also, chr also, take the one solution that you want – Ionut Flavius Pogacian Aug 02 '13 at 13:24
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but, if only 1 char needs to be ascaped, i recomend chr function – Ionut Flavius Pogacian Aug 02 '13 at 13:28
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1@IonutFlaviusPogacian Well I hope this is a simplified version of the actual regex, otherwise a simple `str_replace()` would do the job. Why I don't like the `chr(92)` technique is because you will have an ugly concatenation in the actual regex. Although this is just a preference :) – HamZa Aug 02 '13 at 13:31
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c'est la vie; i assumed that he does not understand regex yet – Ionut Flavius Pogacian Aug 02 '13 at 13:49
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Try the php chr() function and tell the preg_replace the char ascii code for \ and \\.
<?php
echo chr(52) . "<br>"; // Decimal value
echo chr(052) . "<br>"; // Octal value
echo chr(0x52) . "<br>"; // Hex value
preg_replace(chr(1),chr(2),'text'),
?>
Ionut Flavius Pogacian
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This works: (using str_replace() rather than preg_replace())
$str = "text to \ be parsed";
$str = str_replace('\\', '\\\\', $str);
echo $str;
JohnnyFaldo
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