If you want the directory where you're currently at, you can get that from %cd%. That's your current working directory.
If you're going to be changing your current working directory during the script execution, just save it at the start:
set startdir=%cd%
then you can use %startdir% in your code regardless of any changes later on (which affect %cd%).
If you just want to get the last component of that path (as per your comment), you can use the following as a baseline:
    @setlocal enableextensions enabledelayedexpansion
    @echo off
    set startdir=%cd%
    set temp=%startdir%
    set folder=
:loop
    if not "x%temp:~-1%"=="x\" (
        set folder=!temp:~-1!!folder!
        set temp=!temp:~0,-1!
        goto :loop
    )
    echo.startdir = %startdir%
    echo.folder   = %folder%
    endlocal && set folder=%folder%
This outputs:
    C:\Documents and Settings\Pax> testprog.cmd
    startdir = C:\Documents and Settings\Pax
    folder   = Pax
It works by copying the characters from the end of the full path, one at a time, until it finds the \ separator. It's neither pretty nor efficient, but Windows batch programming rarely is :-)
EDIT
Actually, there is a simple and very efficient method to get the last component name.
for %%F in ("%cd%") do set "folder=%~nxF"
Not an issue for this situation, but if you are dealing with a variable containing a path that may or may not end with \, then you can guarantee the correct result by appending \.
for %%F in ("%pathVar%\.") do set "folder=%~nxF"