I wouldn't rely upon a Dictionary. I'd use custom types.
For example, let's assume that:
In that case, you might use a very simple generic pattern:
struct Person: Decodable {
let name: String
}
struct Location: Decodable {
let x: Int
let y: Int
}
struct ServerResponse<T: Decodable>: Decodable {
let type: String
let data: T
}
And then, when you want to parse a response with a Person, it would be:
let data = json.data(using: .utf8)!
do {
let responseObject = try JSONDecoder().decode(ServerResponse<Person>.self, from: data)
let person = responseObject.data
print(person)
} catch let parseError {
print(parseError)
}
Or to parse a Location:
do {
let responseObject = try JSONDecoder().decode(ServerResponse<Location>.self, from: data)
let location = responseObject.data
print(location)
} catch let parseError {
print(parseError)
}
There are more complicated patterns one could entertain (e.g. dynamic parsing of the data type based upon the type value it encountered), but I wouldn't be inclined to pursue such patterns unless necessary. This is a nice, simple approach that accomplishes typical pattern where you know the associated response type for a particular request.
If you wanted you could validate the type value with what was parsed from the data value. Consider:
enum PayloadType: String, Decodable {
case person = "person"
case location = "location"
}
protocol Payload: Decodable {
static var payloadType: PayloadType { get }
}
struct Person: Payload {
let name: String
static let payloadType = PayloadType.person
}
struct Location: Payload {
let x: Int
let y: Int
static let payloadType = PayloadType.location
}
struct ServerResponse<T: Payload>: Decodable {
let type: PayloadType
let data: T
}
Then, your parse function could not only parse the right data structure, but confirm the type value, e.g.:
enum ParseError: Error {
case wrongPayloadType
}
func parse<T: Payload>(_ data: Data) throws -> T {
let responseObject = try JSONDecoder().decode(ServerResponse<T>.self, from: data)
guard responseObject.type == T.payloadType else {
throw ParseError.wrongPayloadType
}
return responseObject.data
}
And then you could call it like so:
do {
let location: Location = try parse(data)
print(location)
} catch let parseError {
print(parseError)
}
That not only returns the Location object, but also validates the value for type in the server response. I'm not sure it's worth the effort, but in case you wanted to do so, that's an approach.
If you really don't know the type when processing the JSON, then you just need to write an init(coder:) that first parses the type, and then parses the data depending upon the value that type contained:
enum PayloadType: String, Decodable {
case person = "person"
case location = "location"
}
protocol Payload: Decodable {
static var payloadType: PayloadType { get }
}
struct Person: Payload {
let name: String
static let payloadType = PayloadType.person
}
struct Location: Payload {
let x: Int
let y: Int
static let payloadType = PayloadType.location
}
struct ServerResponse: Decodable {
let type: PayloadType
let data: Payload
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
type = try values.decode(PayloadType.self, forKey: .type)
switch type {
case .person:
data = try values.decode(Person.self, forKey: .data)
case .location:
data = try values.decode(Location.self, forKey: .data)
}
}
enum CodingKeys: String, CodingKey {
case type, data
}
}
And then you can do things like:
do {
let responseObject = try JSONDecoder().decode(ServerResponse.self, from: data)
let payload = responseObject.data
if payload is Location {
print("location:", payload)
} else if payload is Person {
print("person:", payload)
}
} catch let parseError {
print(parseError)
}