Given a generic type declaration C<F1,...,Fn> (n > 0), the direct
supertypes of the parameterized type C<T1,...,Tn>, where Ti (1 ≤ i ≤
n) is a type, are all of the following:
D<U1 θ,...,Uk θ>, where D<U1,...,Uk> is a generic type which is a
direct supertype of the generic type C<F1,...,Fn> and θ is the
substitution [F1:=T1,...,Fn:=Tn].
Let us see an example.
public class D<U1,U2> {
}
//Note the order of F3,F4.
class C<F1,F2,F3,F4> extends D<F4,F3>{
}
class Main{
public static void main(String[] args) {
C<Integer,String,Float,Number> obj = new C<>();
D<Float ,Number> obj2 = obj; // Compilation error
D<Number ,Float> obj3 = obj; //This is fine
}
}
What do you think θ is here ?
θ = [F1:= Integer , F2:= String, F3:= Float, F4:= Number ]
Now D<Number,Float> is the correct supertype. But not D<Float,Number>. Why ?
Because of Ui θ. So what does this mean ?
Well , it just means substitute i.e. Scan U1 , U2 , ... till Uk and if you find any Fi , then replace it by Ti.
In our example , it means Scan F4 and F3 of class D. Did you have F4 and F3 in θ ? Yes.
Then F4,F3 of D have to be as defined in θ.
Note : The answer is as per my understanding. I don't have any concrete reference of what Uk θ means in Java type semantics.