I have a function that looks at the provided children and if a particular element type is found, it adds some properties to it automatically.
The function is called like this:
render () {
    const { children, name, className } = this.props;
    return (
        <div className={className}>
            {this.enrichRadioElements(children, name)}
        </div>
    )
}
and it is implemented like this:
enrichRadioElements = (children: Array<any>, name: string) => (
    React.Children.map(children, child => {
        if (!React.isValidElement(child)) {
            return child;
        }
        //@ts-ignore
        if (child.props.children) {
            child = React.cloneElement(child, {
                //@ts-ignore
                children: this.enrichRadioElements(child.props.children, name)
            });
        }
        if (child.type === Radio) {
            return React.cloneElement(child, { 
                onChange: this.handleFieldChange,
                selectedValue: this.state.selectedValue,
                name: name
            })
        }
        else {
            return child;
        }
    })
)
The two //@ts-ignore comments are what I'm trying to get rid of by writing code that will satisfy typescript. If I remove the first one, the error message I see is this:
Property 'children' does not exist on type '{}'.(ts-2339)
How can I properly modify my code so I can remove the //@ts-ignore comments? I did go to the definition of child.props and I found this:
interface ReactElement<P = any, T extends string | JSXElementConstructor<any> = string | JSXElementConstructor<any>> {
    type: T;
    props: P;
    key: Key | null;
}
which looks to have a 'props' of type any (if I'm reading it correctly), but typescript doesn't recognize the children property.