How to differentiate between debug and release mode in flutter in code?

Question

I want to have some functionality only in release mode, and not in debug. It's longer to get past it and just commenting it during development is not a good idea. As there is always a probability of forgetting about it when making release builds.

see https://flutter.dev/docs/testing/debugging#debug-mode-assertions — pskink, Apr 10 '19 at 07:15

score 25 · Accepted Answer · answered Apr 10 '19 at 07:18

25

By importing flutter/foundation.dart, a top level constant is available for this check:

kReleaseMode

This is better than asserts, because it works with tree shaking.

answered Apr 10 '19 at 07:18

Rémi Rousselet

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3

What do you mean by tree shaking? – RoyalGriffin Apr 10 '19 at 08:59
8

The compiler will remove unused code. So if you're doing `if (kReleaseMode) {} else {}` then the compiler knows that the `else` will never be executed, and therefore remove it. – Rémi Rousselet Apr 10 '19 at 12:33

Kalpesh Kundanani · Answer 2 · 2019-04-10T08:54:53.073

This worked well for me. Declare a function like following;

bool get isInDebugMode {
  bool inDebugMode = false;
  assert(inDebugMode = true);
  return inDebugMode;
}

Now you can use it like:

if(isInDebugMode) {
    print('Debug');
} else {
    print('Release');
}

Source of information

======================================================================== You can also use solution given by @Rémi Rousselet:

First import the package:

import 'package:flutter/foundation.dart';

and use kReleaseMode like this:

if(kReleaseMode) { // is in Release Mode ?
    print('Release');
} else {
    print('Debug');
}

How to differentiate between debug and release mode in flutter in code?

2 Answers2