None of the provided answers allow to separate stdout and stderr so I try another answer.
First you get all the info you need, if you look at the documentation of the exec.Cmd type in the os/exec package. Look here: https://golang.org/pkg/os/exec/#Cmd
Especially the members Stdin and Stdout,Stderr where any io.Reader can be used to feed stdin of your newly created process and any io.Writer can be used to consume stdout and stderr of your command.
The function Shellout in the following programm will run your command and hand you its output and error output separatly as strings.
As the parameter value is executed as a shell command, sanitize
all external inputs used in the construction of the parameter
value.
Probably don't use it in this form in production.
package main
import (
"bytes"
"fmt"
"log"
"os/exec"
)
const ShellToUse = "bash"
func Shellout(command string) (string, string, error) {
var stdout bytes.Buffer
var stderr bytes.Buffer
cmd := exec.Command(ShellToUse, "-c", command)
cmd.Stdout = &stdout
cmd.Stderr = &stderr
err := cmd.Run()
return stdout.String(), stderr.String(), err
}
func main() {
out, errout, err := Shellout("ls -ltr")
if err != nil {
log.Printf("error: %v\n", err)
}
fmt.Println("--- stdout ---")
fmt.Println(out)
fmt.Println("--- stderr ---")
fmt.Println(errout)
}
