Using substr() and strlen() to get a file name

Question

Below is my code. If $varPath is ../../folder1/home/ and If $varNam is house.png I need $name to be house. How can I fix this?

$varPath = htmlentities('../../folderA/'.$_POST['sVar']).'/');
$varExt = '*.*';
$varNam = glob($varPath.$varExt);

$name = substr($varNam,strlen($varPath),strpos($varNam, '.') - strlen($varPath);

Look at the phpinfo and basename functions. – Holt May 13 '14 at 09:42 — Holt, May 13 '14 at 09:42

Dexa · Accepted Answer · 2014-05-13T09:48:40.487

1

$varPath = '../../folder1/home/';
echo basename($varPath);

Output: home

EDIT:

In order to remove any extension use pathinfo

$path_parts = pathinfo('../../folder1/home/house.png');
echo $path_parts['filename'];

Output: house

edited May 13 '14 at 09:48

answered May 13 '14 at 09:42

Dexa

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The OP is asking about removing file extensions, not extract the folder name. – Theolodis May 13 '14 at 09:45
@Theolodis Edited, thanks, didn't pay attention. – Dexa May 13 '14 at 09:49
No problem, but consider taking your time to understand the question and write a good answer. That's worth way more than trying to go for the easy reputation ;) – Theolodis May 13 '14 at 09:50

Klemen Tusar · Answer 2 · 2014-05-13T09:49:49.230

0

Improved answer

<?php
$path = '/var/www/html/project/images/house.png';
$pathinfo = pathinfo($path);

echo str_replace(".{$pathinfo['extension']}", '', $pathinfo['basename']);

This will produce "house" no matter what the extension.

edited May 13 '14 at 09:49

answered May 13 '14 at 09:42

Klemen Tusar

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4
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He does probably need to remove file endings, any of them.. e.g. /x/y/file1.jpeg, y/x/file2.png, etc... – Theolodis May 13 '14 at 09:46
`path_info['filename']` does not contain the extension, does it? – Theolodis May 13 '14 at 09:54
@Theolodis Oh, that one exists too? Since when? :D – Klemen Tusar May 13 '14 at 09:57
True. Missed that completely.... – Klemen Tusar May 13 '14 at 10:00

Using substr() and strlen() to get a file name

2 Answers2