How to print output of for loop on same line

Question

Here is my code:

def missing_ch(number, string):
      for i in range(len(string)):
        if i==number:
           continue
        else:   
           print(string[i], end=' ')
      return
string='hello'
num=int(input("enter the position of char"))
missing_ch(num, string)

How to get output characters printed in same line?

What's the error you get ? I'm willing to bet that your code doesn't work because of syntax errors ... did you read the console output ? — Dimitri Mockelyn, Jul 02 '15 at 07:25
`if(ch==num)` variable `ch` doesn't declared in your function... also there are a lot of mistakes to remove: `(int)()`=`int()`, `if()`=just `if`, `range(len(str)`=`range(len(str))` — Andersson, Jul 02 '15 at 07:31
I did a mistake in writing but my code was right I checked it with console output — user5072614, Jul 02 '15 at 07:42
I was getting out put on new line but I want to make it on same line — user5072614, Jul 02 '15 at 07:44
possible duplicate of [Python print on same line](http://stackoverflow.com/questions/5598181/python-print-on-same-line) — Mel, Jul 02 '15 at 08:21

score 0 · Answer 1 · answered Jul 02 '15 at 07:31

I see 3 issues in your program -

In the for loop in second line , you have missed closing a bracket - for i in range (len(str): , it should be - for i in range (len(str)):
There is no casting in python, to convert input to string, you have use int function, as int(...) , so your line (int)(input(...)) should be - int(input(...)) .
In your for loop, you are defining the index as i, but you are using ch inside the loop, you should be using i instead of `ch.

Example -

    for i in range (len(str):
        if(i==num):
            continue
        print(str[i],end=' ')
    return

The print statement to print items without appending the newline is fine, it should be working.

A working example -

>>> def foo():
...     print("Hello",end=" ")
...     print("Middle",end=" ")
...     print("Bye")
...
>>> foo()
Hello Middle Bye

score 0 · Answer 2 · answered Jul 02 '15 at 07:37

To print on one line, you could append each letter on a string.

def missing_ch(num, str):
  result = ""
  for i in range (len(str)):
    if (i == num):
      continue
    result+=str[i]
  print result

string = 'hello'
num = (int)(input('enter the position of char'))

missing_ch(num, string)

#>helo

score -1 · Answer 3 · edited Oct 11 '19 at 19:09

-1

I'm new into python and my friend is giving me tasks to perform and one of them was to print a square made out of "*" and this is how I did it:

br = int(input("Enter a number: "))

for i in range(0, br):
    print("*" * br)

edited Oct 11 '19 at 19:09

Dharman

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answered Oct 11 '19 at 18:08

user12202710

1

How to print output of for loop on same line

3 Answers3