In Java, the && and || are short circuit. Thus, they do not evaluate their second operand if not necessary (e.g. false && a, true || b).
What about the &= operator? Is it short circuit as well?
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Claas Wilke
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`&` is not a short circuit operator, so `a = a & b` doesn't short circuit, nor does `a &= b;` – Peter Lawrey Jul 08 '15 at 10:37
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No, &= is not a boolean operator and as such it does not short-circuit anything, it's a bitwise assignment operator.
It essentially implies assigning first operand with bitwise & of first and second operands.
Quick demo
int i = 01;
int ii = 10;
System.out.println(i &= ii); // assigns i with i & ii and sends i to print stream
i = 01;
ii = 11;
System.out.println(i &= ii);
Output
0
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Mena
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No, it's not.
There was a thread a while back about why doesn't a &&= operator exist. That could've been a short-circuit operator, if it made sense to have it.
Kayaman
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