preg_replace and big brackets {}

Question

I want to make an email template and how to replace everything in the brackets {}and with the brackets{}?

$template = "My name is {NAME}. I'm {AGE} years old.";
$template = preg_replace("{NAME}", "Tom", $template);
$template = preg_replace("{AGE}", "10", $template);

and after that should look like this: My name is Tom. I'm 10 years old.

possible duplicate of [Simple PHP string replace?](http://stackoverflow.com/questions/5644947/simple-php-string-replace) — FirstOne, Jul 17 '16 at 14:42

score 5 · Answer 1 · answered Jul 17 '16 at 14:34

5

Use str_replace instead of preg_replace:

$template = "My name is {NAME}. I'm {AGE} years old.";
$template = str_replace("{NAME}", "Tom", $template);
$template = str_replace("{AGE}", "10", $template);

answered Jul 17 '16 at 14:34

Lakremon

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score 1 · Answer 2 · answered Jul 17 '16 at 14:35

1

Regex pattern should have delimiter at start and end of it

$template = "My name is {NAME}. I'm {AGE} years old.";
$template = preg_replace("/{NAME}/", "Tom", $template);
echo $template = preg_replace("/{AGE}/", "10", $template);

answered Jul 17 '16 at 14:35

splash58

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Alive to die - Anant · Accepted Answer · 2016-07-18T04:17:12.083

1

You can use preg_replace() with single line like below (better than str_replace()):-

$template = "My name is {NAME}. I'm {AGE} years old.";
$find = array('/{NAME}/', '/{AGE}/');
$replace = array('TOM', '10');
$template = preg_replace($find, $replace, $template);

echo $template;

Output:- https://eval.in/606528

Note:- it have below benefits:-

1. Single line code to replace all you want. not needed again and again str_replace().

2. If some more replacement needed in future then you have to add them into $find and $replace and that's it. So it is more flexible.

Sorry i totally forgot to mention that str_replace() will also works with array so you can do it like below too:-

<?php

$template = "My name is {NAME}. I'm {AGE} years old.";
$find = array('{NAME}', '{AGE}');
$replace = array('TOM', '10');
$template = str_replace($find, $replace, $template);

echo $template;

Output:-https://eval.in/606577

Note:- Both are equally good. You can go for any one. Thanks

edited Jul 18 '16 at 04:17

answered Jul 17 '16 at 14:44

Alive to die - Anant

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What about the escapement? Aren't braces a reserved character in regex? – RamenChef Jul 17 '16 at 14:54
@RamenChef no php regex works in a different way – Alive to die - Anant Jul 17 '16 at 15:15
I like the way of arrays but it why not replace preg_replace() function with str_replace() it works fine with the arrays? I haven't thought about str_replace before and it seems to be better in my case. – soonic Jul 17 '16 at 17:28

score 1 · Answer 4 · answered Jul 17 '16 at 14:53

preg_replace is not the right function to use in this situation. In this case, the correct option would be str_replace or str_ireplace. However, for a large amount of data to format, using regex would be a better idea:

$associative_formatter_array = array('NAME' => 'Tom', "AGE" => '10');
$template = "My name is {NAME}. I'm {AGE} years old.";
$template = preg_replace_callback("`\{([^\}]*)\}`g", function($match) {
  return $_GLOBALS["associative_formatter_array"][$match[1]];
});

preg_replace and big brackets {}

4 Answers4