I dont want to use html file, but only with django I have to make POST request.
Just like urllib2 sends a get request.
I dont want to use html file, but only with django I have to make POST request.
Just like urllib2 sends a get request.
Here's how you'd write the accepted answer's example using python-requests:
post_data = {'name': 'Gladys'}
response = requests.post('http://example.com', data=post_data)
content = response.content
Much more intuitive. See the Quickstart for more simple examples.
In Python 2, a combination of methods from urllib2 and urllib will do the trick. Here is how I post data using the two:
post_data = [('name','Gladys'),] # a sequence of two element tuples
result = urllib2.urlopen('http://example.com', urllib.urlencode(post_data))
content = result.read()
urlopen() is a method you use for opening urls. urlencode() converts the arguments to percent-encoded string.
The only thing you should look at now:
You can use urllib2 in django. After all, it's still python. To send a POST with urllib2, you can send the data parameter (taken from here):
urllib2.urlopen(url[, data][, timeout])
[..] the HTTP request will be a POST instead of a GET when the data parameter is provided
Pay attention, that when you're using requests , and make POST request passing your dictionary in data parameter like this:
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', data=payload)
you are passing parameters form-encoded.
If you want to send POST request with only JSON (most popular type in server-server integration) you need to provide a str() in data parameter. In case with JSON, you need to import json lib and make like this:
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', data=json.dumps(payload))`
documentation is here
OR:
just use json parameter with provided data in the dict
payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', json=payload)`