JS Regex: How to capture repeating pattern into different array elements?

Question

For example, I have a target string like: str='Every "red","white","blue" flower is $7.'

If I run /Every ("(.+)",?)+ flower is \$(.+)/.exec(str), I will get "red","white","blue" as a whole output element, but what I want is ["red,"white","blue"].

Is there a way to do this, or I can only use split?

Thanks!

If the double-quotes are balanced, either lookbehind for `"` in a global `.match` while matching non-`"`s, or repeatedly exec `"([^"]+)"` and extract the first group — CertainPerformance, Nov 26 '18 at 03:13

score 1 · Accepted Answer · answered Nov 26 '18 at 04:31

1

A global parameter RegExp and a String.match() solution would be the most practical:

str.match(/"(.*?)"/g) // [ '"red"', '"white"', '"blue"' ]

answered Nov 26 '18 at 04:31

GMaiolo

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Is this able to be modified to also capture other patterns like the tail `$7`? – Romulus Urakagi Ts'ai Nov 26 '18 at 04:43
@RomulusUrakagiTs'ai yes doing something like `/("(.*?)")|(\$\d+)/g` would catch that format as well – GMaiolo Nov 26 '18 at 16:24
Hmm, this is a bit different from what I want to ask, but I think I can use the combination. Thank you. – Romulus Urakagi Ts'ai Nov 27 '18 at 07:47

JS Regex: How to capture repeating pattern into different array elements?

1 Answers1