A-level Chemistry/WJEC/Module 2/Thermochemistry
Energy Change
Energetics is all about the energy transfer involved in the making and breaking of bonds. The breaking of a bond involves the injection of energy into the system so that the bond can no longer hold the parts together; the creation of bonds involves the removal of energy from the system so that components are captured by the binding forces. In a typical reaction some bonds are broken and some are created so some energy is injected and some is removed. Whether the total(net) of these amounts to an injection or removal determines whether the reaction is endothermic (involving an net injection of energy) or exothermic (involving a net removal of energy.)
Enthalpy change (ΔH)
The simple idea described above is complicated by the interaction of the system (reaction) being studied and its environment. This interaction amounts to the changes in volume of the system brought about by the reaction. To deal with this complexity we introduce the idea of enthalpy (given the symbol H). Enthalpy is not measured directly: we concern ourselves instead with CHANGES in enthalpy (ΔH) resulting from a reaction.
For a given reaction, change in enthalpy is equal to the heat energy change under conditions of constant pressure.
- Enthalpy change
- The heat energy transferred under constant pressure.
- ΔH = H(products) – H(reactants) = mcΔT ÷ n
Exothermic
- negative ΔH
Such reactions include the combustion of a fuel like methane CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l) = -890 kJ mol−1 Also including the oxidation of carbohydrates such as glucose C6H12O6
Endothermic
- positive ΔH
Such reactions include the thermal decomposition of calcium carbonate CaCO3(s) → CaO(s) + CO2(g) = +178 kJ mol−1
- Standard conditions
We often deal with enthalpy change under standard conditions. i.e.
- 101 kPa, 298 K (WJEC use 1 atm = 101 kPa as standard pressure and 25 °C = 298 K for standard temperature).
- Standard enthalpy of formation
- ΔfH⦵
- The enthalpy change when 1 mole of compound in its standard state is formed from its elements in their standard states (under standard conditions).
- Standard enthalpy of combustion
- ΔcH⦵
- The enthalpy change when 1 mole of substance is completely burned in oxygen under standard conditions.
Calorimetry
Calculating energy changes
- q = mcΔT
- heat energy = mass of substance x specific heat capacity x temperature change
- ΔH = q ÷ n
- enthalpy change = heat energy ÷ amount
Hess's Law
- Hess's Law
- The overall enthalpy change is independent of the route the chemical reaction takes place.
(Average) Bond Enthalpy, Ed
The enthalpy of a reaction which breaks 1 mole of a certain type of covalent bond by homolytic fission, under standard conditions.
Example:
Breaking 1 mole of Cl-Cl bonds:
Cl2(g) → 2 Cl(g) Ed = 243 kJ mol-1
Except for bonds which form diatomic molecules, multiple molecules can contain the same type of bond. For example, only Cl2 has a Cl-Cl bond, but the C-Cl bond is present in a very wide range of compounds (CH3Cl, CCl4, CH3CCl3, etc). For most covalent bonds, we can look up the average bond enthalpy to find an estimate of the strength of the bond in a specific compound.
Ed is always positive because breaking bonds requires energy. Some biologist like to say that "breaking the phosphate bond in ATP releases energy" but this is wrong. Breaking the phosphate bond in ATP requires energy, like any bond-breaking process. When ADP and phosphate form from ATP and water, the new bonds formed in ADP and phosphate release more energy than was required to break the bonds in ATP and water.
We can estimate the energy of a reaction from the bond energies involved:
- ΔrH⦵ = Σ (Ed(bonds broken)) - Σ (Ed(bonds made))
The ΔrH⦵ value calculated is not an exact figure, because the bond energies are average values and are not exactly the bond energies in the specific reaction.