Turing/Solution 1
< Turing
var n : int %User input
var ctr : int := 0 %Counter variable
var gotit : boolean %Stores if fractorial is found
get n
loop
ctr := 0 %ctr is NEVER actually used as zero, since that would cause a division by 0 error.
loop
gotit := true %Initially assume that fractorial has been found, and change to false if found otherwise
ctr += n %Increase counter by n
for i : 1 .. n %Try n/1, n/2, n/3... until n/i. If all are whole numbers, then answer has been found
if ctr / i not= ctr div i then
gotit := false
end if
end for
exit when gotit = true
end loop
if gotit = true then
put "Fractorial (", n, ") = ", ctr
exit
end if
end loop
While you might try ctr += 1 initially, it will quickly become evident that this is too slow. Through logical reasoning and some experimentation, you should be able to discover that the fractorial of n is a multiple of n.