Umbraco/Samples and Articles/Macros
A macro for getting the url of an image
Go to Developer/XSLT Files, create a new xslt file GetImageURL with the following content:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:Stylesheet [ <!ENTITY nbsp " "> ]>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxml="urn:schemas-microsoft-com:xslt"
xmlns:umbraco.library="urn:umbraco.library"
exclude-result-prefixes="msxml umbraco.library">
<xsl:output method="xml" omit-xml-declaration="yes" />
<xsl:param name="currentPage"/>
<xsl:variable name="imageID" select="/macro/imageID/node/@id"/>
<xsl:template match="/">
<xsl:if test="$imageID != ''">
<img>
<xsl:attribute name="src">
<xsl:value-of select="umbraco.library:GetMedia($imageID, 'false')/data [@alias = 'umbracoFile']"/>
</xsl:attribute>
</img>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Now go to Developer/Macros, create a new macro, Get Image URL, giving it the alias GetImageURL. In Use XSLT File, select the XSLT file you just created.
On Parameters, add a new parameter with the alias imageID and name Image ID. The type should be set to mediaCurrent and Show should be checked. Save the macro and your home!