The Men’s Singles tournament of the 2006 BCR Open Romania tennis championship took place in Bucharest, Romania, between 11 September and 17 September 2006. 32 players from 13 countries competed in the 5-round tournament. The final winner was Jürgen Melzer of Austria, who defeated Filippo Volandri of Italy.[1] The defending champion from 2005, Florent Serra, lost in the semifinals to Volandri.[2]
Seeds
Draw
Key
Finals
Top half
Bottom half
References
External links
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Grand Slam events | |
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ATP Masters Series | |
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ATP International Series Gold | |
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ATP International Series |
- Adelaide (S, D)
- Doha (S, D)
- Chennai (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Delray Beach (S, D)
- Marseille (S, D)
- San Jose (S, D)
- Scottsdale (S, D)
- Estoril (S, D)
- Valencia (S, D)
- Houston (S, D)
- Munich (S, D)
- Casablanca (S, D)
- Pörtschach (S, D)
- Halle (S, D)
- London (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Amersfoort (S, D)
- Umag (S, D)
- Los Angeles (S, D)
- New Haven (S, D)
- Bucharest (, D)
- Stockholm (S, D)
- Moscow (S, D)
- St. Petersburg (S, D)
- Lyon (S, D)
- Basel (S, D)
- Mumbai (S, D)
- Viña del Mar (S, D)
- Zagreb (S, D)
- Buenos Aires (S, D)
- Sopot (S, D)
- Costa do Sauípe (S, D)
- Indianapolis (S, D)
- Washington (S, D)
- Bangkok (S, D)
- Palermo (S, D)
- Metz (S, D)
- Beijing (S, D)
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Team events | |
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