I wrote a code to download an image from internet. And i have to show it in a ImageView which is dynamically created.
And i am getting an error that Only the original thread that created a view hierarchy can touch its views. I know i have to write a handle but how can i do that?
Here is my code:
public class ResimCek implements Runnable {
        int resimID = 0;
        public ResimCek(int parcaID) {
            // store parameter for later user
            resimID = parcaID;
        }
        public void run() {
            int resID = getResources().getIdentifier(Integer.toString(resimID) , "tag", getPackageName()); 
            ImageView resim = (ImageView) findViewById(resID);
            Drawable image = ImageOperations(getBaseContext(),"http://141.11.11.206/parca/" + Integer.toString(resimID) + ".jpg" ,"I" + Integer.toString(resimID) + ".jpg");
            // I AM GETTING ERROR HERE ******************
            resim.setImageDrawable(image); // *************************
        }
    }
    private Drawable ImageOperations(Context ctx, String url, String saveFilename) {
        try {
            InputStream is = (InputStream) this.fetch(url);
            Drawable d = Drawable.createFromStream(new URL(url).openConnection().getInputStream(),saveFilename);
            return d;
        } catch (MalformedURLException e) {
            e.printStackTrace();
            return null;
        } catch (IOException e) {
            e.printStackTrace();
            return null;
        }
    }
    public Object fetch(String address) throws MalformedURLException,IOException {
        URL url = new URL(address);
        Object content = url.getContent();
        return content;
    }
    private void MalzemeEkle(String malzemeKodu, String malzemeTanimi) {
        ImageView parcaresmi = new ImageView(this);
        parcaresmi.setId(Integer.parseInt(malzemeKodu));
        Runnable r = new ResimCek(Integer.parseInt(malzemeKodu)); 
        new Thread(r).start(); 
}
 
     
     
     
    