In ShellViewModel I have below command binding to open a new window "Remote View"
public ICommand RemoteViewCommand
{
    get { return new RelayCommand(RemoteViewExecute, CanRemoteViewExecute); }
}
private void RemoteViewExecute()
{
    if (!CanRemoteViewExecute())
    {
        return;
    }
    var shellRemoteView = Application._Container.Resolve<ShellRemoteView>();
    if (_ShellRemoteView.DataContext==null)
        _ShellRemoteView.DataContext = Application._Container.Resolve<ShellRemoteViewModel>();        
    shellRemoteView.Show();
}
On startup I have already registered both "ShellRemoteView" and "ShellRemoteViewModel" using lifetime managers to have singleton instance.
_Container.RegisterType<ShellRemoteView>(new ContainerControlledLifetimeManager());
_Container.RegisterType<ShellRemoteViewModel>(new ContainerControlledLifetimeManager());
When shellRemoteView.Show() executed and I close the form, then again on calling shellRemoteView.Show() I'm getting Invalid Operation excepton:Cannot set Visibility or call Show, ShowDialog, or WindowInteropHelper.EnsureHandle after a Window has closed.
Is there is any work-around in Unity to get window instance again if its closed.
 
     
    