getting position in a list and then display a web view

Question

Hey I am trying to display a web view if someone clicks on the 5th item in a list.

This is the code:

          lv.setOnItemClickListener(new OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> a, View v, int position,
                long id) {

            if (position == 5) {

                Intent intent = new Intent(Intent.ACTION_VIEW);
                Uri uri = Uri.parse(href2_final
                                + "=service&doc_library=ABN01&doc_number="
                                + record_parsed_final
                                + "&line_number=0001&func_code=WEB-FULL&service_type=MEDIA");
                intent.setData(uri);
                startActivity(intent);
            }

        }

    });

What am I doing wrong? If I delete the IF statement then it will launch the web view when i press any item in the list.

Thanks!

loool this is hilarious! position == 5 is definitely the 5th item — Sherif elKhatib, Apr 26 '12 at 22:11
@SherifelKhatib: are you sure? I just tested it, and the first element in the list has a value for `position` of zero. — Chopin, Apr 26 '12 at 23:55

score 2 · Accepted Answer · edited May 23 '17 at 12:12

2

As per your code, you must need to select 6th item in your ListView to call startActivity. For more info, read this

edited May 23 '17 at 12:12

Community

1
1

answered Apr 26 '12 at 21:41

waqaslam

67,549
16
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score 0 · Answer 2 · answered Apr 26 '12 at 21:42

0

I guess the fifth element is indexed in the position 4.

answered Apr 26 '12 at 21:42

Chopin

1,442
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getting position in a list and then display a web view

2 Answers2