Windows CMD script to get directory in which file exists

Question

I have a executable file VSTO.exe & a try.bat file in one folder. I want to get the folder path of the bat file & concat that path with VSTO.exe.

I have this script in my try.bat.

"%~fp0\VSTO.exe" /q

but it creates path: "G:\test\try.bat\VSTO.exe" . I want to get a path "G:\test\VSTO.exe"

can anyone tell me how do i do that?

score 7 · Accepted Answer · edited May 23 '17 at 11:56

7

"%~dp0\VSTO.exe" /q

is the exact answer.

How to get folder path from file path with CMD

edited May 23 '17 at 11:56

Community

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answered May 03 '12 at 10:40

Sangram Nandkhile

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Steve · Answer 2 · 2012-05-03T10:50:37.510

1

Try with this

SET CURDIR=%CD%
"%CURDIR%\VSTO.EXE" /q

The %CD% pseudo-variable expands to the current working directory.
Type SET /? to see other pseudo-variable (last page)

edited May 03 '12 at 10:50

answered May 03 '12 at 10:13

Steve

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Do you have extensions enabled? (cmd /x to enable, cmd /y to disable) – Steve May 03 '12 at 10:30
yes. it is giving exception like 'not identified as internal or external command' – Sangram Nandkhile May 03 '12 at 10:38
But that file "VSTO.EXE" is in the current directory where you execute the try.bat? And the current directory contains spaces? (Answer updated to account for directory with spaces) – Steve May 03 '12 at 10:46
If the executable is in the current directory, why not just say .\vsto.exe? – Harry Johnston May 03 '12 at 20:40

Windows CMD script to get directory in which file exists

2 Answers2