This is not a good solution but it works. :)
#######################################
# String_To_OrderedDict
# Convert String to OrderedDict
# Example String
#    txt = "OrderedDict([('width', '600'), ('height', '100'), ('left', '1250'), ('top', '980'), ('starttime', '4000'), ('stoptime', '8000'), ('startani', 'random'), ('zindex', '995'), ('type', 'text'), ('title', '#WXR#@TU@@Izmir@@brief_txt@'), ('backgroundcolor', 'N'), ('borderstyle', 'solid'), ('bordercolor', 'N'), ('fontsize', '35'), ('fontfamily', 'Ubuntu Mono'), ('textalign', 'right'), ('color', '#c99a16')])"
#######################################
def string_to_ordereddict(txt):
    from collections import OrderedDict
    import re
    tempDict = OrderedDict()
    od_start = "OrderedDict([";
    od_end = '])';
    first_index = txt.find(od_start)
    last_index = txt.rfind(od_end)
    new_txt = txt[first_index+len(od_start):last_index]
    pattern = r"(\(\'\S+\'\,\ \'\S+\'\))"
    all_variables = re.findall(pattern, new_txt)
    for str_variable in all_variables:
        data = str_variable.split("', '")
        key = data[0].replace("('", "")
        value = data[1].replace("')", "")
        #print "key : %s" % (key)
        #print "value : %s" % (value)
        tempDict[key] = value
    #print tempDict
    #print tempDict['title']
    return tempDict