IP Address of the machine in PHP gives ::1 but why?

Question

I am trying to fetch the ip address of my machine through php. For that I am writing the code like:

<?php echo  "<br />".$_SERVER['REMOTE_ADDR'];?>

But this piece of code is not working. It is returning "::1". Please help me how to get the actual IP Address.

`$_SERVER['REMOTE_ADDR']` is not the IP address of your machine. — hakre, May 09 '12 at 13:45
Possible duplicates: [Identify server IP address with PHP](http://stackoverflow.com/questions/5800927/identify-server-ip-address-with-php) -- or if you need the other thing -- [How do I find a user's IP address with PHP?](http://stackoverflow.com/questions/55768/how-do-i-find-a-users-ip-address-with-php) — hakre, May 09 '12 at 13:47
Of what machine? Your server that the PHP is running on? Your desktop that the browser connecting to the server is running on? — Quentin, May 09 '12 at 13:47
`::1` is the actual IP. It is an ipv6 loopback address (i.e. localhost) — Quentin, May 09 '12 at 13:47
if you run that php script on the server itself of course it will return ::1 (i.e. localhost). Put the script on different server. — Daniel Wu, Feb 17 '21 at 04:32

Quentin · Accepted Answer · 2013-01-22T09:39:13.957

87

::1 is the actual IP. It is an ipv6 loopback address (i.e. localhost). If you were using ipv4 it would be 127.0.0.1.

If you want to get a different IP address, then you'll need to connect to the server through a different network interface.

edited Jan 22 '13 at 09:39

answered May 09 '12 at 13:48

Quentin

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Perfectly well explained! – Jun 10 '22 at 08:48

score 14 · Answer 2 · edited May 23 '17 at 11:47

14

If you are trying to run localhost, this answer will fix your problem. Just few changes on

apache2/httpd.conf

search all "listen" words ex:

Listen 80

Make like this.

Listen 127.0.0.1:80

than restart your apache

$_SERVER[REMOTE_ADDR]

will show Listen 127.0.0.1

you can see answer in this detailed answer link

edited May 23 '17 at 11:47

Community

1
1

answered Jan 21 '16 at 13:13

Yigit Tanriverdi

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score 8 · Answer 3 · answered May 09 '12 at 13:47

8

If you mean getting the user's IP address, you can do something like :

<?php
    if(!empty($_SERVER['HTTP_CLIENT_IP'])){
      $ip=$_SERVER['HTTP_CLIENT_IP'];
    }
    elseif(!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){
      $ip=$_SERVER['HTTP_X_FORWARDED_FOR'];
    }
    else{
      $ip=$_SERVER['REMOTE_ADDR'];
    }
?>

<?php echo  "<br />".$ip;?>

It will get the user's actual IP address, regardless of proxies etc.

answered May 09 '12 at 13:47

Guillaume Flandre

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1

It's not answer on the question that was asked, but it's useful thing. – Leri May 09 '12 at 13:50
I assumed that's what the OP actually meant, but I might be wrong – Guillaume Flandre May 09 '12 at 13:51
I think he/she was just curious why `$_SERVER['REMOTE_ADDR']` returns `::1`. Maybe I am wrong. Whatever +1 from me. – Leri May 09 '12 at 13:55
4

This answer is very insecure, as anyone can set an "X-Forwarded-For" header and spoof another IP. – DisgruntledGoat Jan 23 '16 at 20:12

score 4 · Answer 4 · answered May 09 '12 at 13:46

4

$_SERVER['REMOTE_ADDR'] is the IP address of the client.

$_SERVER['SERVER_ADDR'] is the IP address of the server.

Reference: http://php.net/manual/en/reserved.variables.server.php

answered May 09 '12 at 13:46

Tushar

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score -1 · Answer 5 · answered Apr 27 '18 at 04:37

Simple answer: You are using it on local server. Try running

function getUserIpAddr(){
    if(!empty($_SERVER['HTTP_CLIENT_IP'])){
        //ip from share internet
        $ip = $_SERVER['HTTP_CLIENT_IP'];
    }elseif(!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){
        //ip pass from proxy
        $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
    }else{
        $ip = $_SERVER['REMOTE_ADDR'];
    }
    return $ip;
}

echo 'User Real IP - '.getUserIpAddr();

in real server. Or you can also user online php executor.

score -2 · Answer 6 · answered May 09 '12 at 13:46

-2

Look at the output of phpinfo(). If the address is not on that page, then the address is not available directly through PHP.

answered May 09 '12 at 13:46

dotancohen

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'$http_client_ip= $_SERVER['HTTP_CLIENT_IP']; $http_x_forwarded_for=$_SERVER['HTTP_X_FORWARDED_FOR']; $remote_addr=$_SERVER['REMOTE_ADDR']; if(!empty($http_client_ip)) {$ip_address=$http_client_ip;} else if(!empty($http_x_forwarded_for)) {$ip_address=$http_x_forwarded_for;} else {$ip_address=$remote_addr;} echo $ip_address;' – roger nm Aug 18 '15 at 11:33
3

Why the sudden downvote? This answer shows that the information either **is** or **is not** available to PHP. – dotancohen May 10 '16 at 10:48

IP Address of the machine in PHP gives ::1 but why?

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