How to access List elements

Question

I have a list

list = [['vegas','London'],['US','UK']]

How to access each element of this list?

Answer 1

I'd start by not calling it list, since that's the name of the constructor for Python's built in list type.

But once you've renamed it to cities or something, you'd do:

print(cities[0][0], cities[1][0])
print(cities[0][1], cities[1][1])

Answer 2

It's simple

y = [['vegas','London'],['US','UK']]

for x in y:
    for a in x:
        print(a)

Answer 3

Tried list[:][0] to show all first member for each list inside list is not working. Result will be the same as list[0][:].

So i use list comprehension like this:

print([i[0] for i in list])

which return first element value for each list inside list.

PS: I use variable list as it is the name used in the question. I will not use this as a variable name since it is the basic function list() in Python.

Answer 4

Learn python the hard way ex 34

try this

animals = ['bear' , 'python' , 'peacock', 'kangaroo' , 'whale' , 'platypus']

# print "The first (1st) animal is at 0 and is a bear." 

for i in range(len(animals)):
    print "The %d animal is at %d and is a %s" % (i+1 ,i, animals[i])

# "The animal at 0 is the 1st animal and is a bear."

for i in range(len(animals)):
    print "The animal at %d is the %d and is a %s " % (i, i+1, animals[i])

Answer 5

Recursive solution to print all items in a list:

def printItems(l):
   for i in l:
      if isinstance(i,list):
         printItems(i)
      else:
         print i


l = [['vegas','London'],['US','UK']]
printItems(l)