Remove string after last occurrence of a character

Question

In my application, I am appending a string to create path to generate a URL. Now I want to remove that appended string on pressing back button.

Suppose this is the string:

/String1/String2/String3/String4/String5

Now I want a string like this:

/String1/String2/String3/String4/

How can I do this?

possible duplicate of [How to get the string after last comma in java?](http://stackoverflow.com/questions/9515505/how-to-get-the-string-after-last-comma-in-java) — Barett, Aug 02 '13 at 17:18
i have answered the question .. over [here][1] it is an easy way.. [1]: http://stackoverflow.com/questions/1181969/java-get-last-element-after-split/23075419#23075419 — Zar E Ahmer, Apr 15 '14 at 10:10

score 70 · Accepted Answer · edited Jun 09 '14 at 16:38

70

You can use lastIndexOf() method for same with

if (null != str && str.length() > 0 )
{
    int endIndex = str.lastIndexOf("/");
    if (endIndex != -1)  
    {
        String newstr = str.substring(0, endIndex); // not forgot to put check if(endIndex != -1)
    }
}

edited Jun 09 '14 at 16:38

Matt

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answered May 31 '12 at 06:13

Dheeresh Singh

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Yes I am getting index of last occurrence of "/", but how to remove string after that character?? – Krishna Suthar May 31 '12 at 06:15
1

Thanks Dheeresh. For now, this is fine. I'll ask you if I get any problem. – Krishna Suthar May 31 '12 at 06:25
This would not work for path already ending with "/", consider this path /user/etc/lib/, be careful when handling such scenario. – A.B. May 01 '17 at 18:21

score 49 · Answer 2 · edited Nov 14 '16 at 13:38

49

String whatyouaresearching = myString.substring(0, myString.lastIndexOf("/"))

edited Nov 14 '16 at 13:38

Alex K

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answered May 31 '12 at 06:14

rsan

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"substring", not subString() :) – N Kaushik Nov 17 '15 at 06:20
3

@rsan Great answer, since the string whatyouaresearching includes the last "/" it will be more like: `String whatyouaresearching = myString.substring(0, myString.lastIndexOf("/") + 1)` – John Spax Jun 02 '17 at 08:58

ccpizza · Answer 3 · 2018-09-01T08:32:30.003

You can use org.apache.commons.lang3.StringUtils.substringBeforeLast which is null-safe.

From the javadoc:

// The symbol * is used to indicate any input including null.
StringUtils.substringBeforeLast(null, *)      = null
StringUtils.substringBeforeLast("", *)        = ""
StringUtils.substringBeforeLast("abcba", "b") = "abc"
StringUtils.substringBeforeLast("abc", "c")   = "ab"
StringUtils.substringBeforeLast("a", "a")     = ""
StringUtils.substringBeforeLast("a", "z")     = "a"
StringUtils.substringBeforeLast("a", null)    = "a"
StringUtils.substringBeforeLast("a", "")      = "a"

Maven dependency:

<dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-lang3</artifactId>
    <version>3.8</version>
</dependency>

Zar E Ahmer · Answer 4 · 2015-05-21T07:43:50.050

3

Easiest way is ...

        String path = "http://zareahmer.com/questions/anystring";

        int pos = path.lastIndexOf("/");

        String x =path.substring(pos+1 , path.length()-1);

now x has the value stringAfterlastOccurence

edited May 21 '15 at 07:43

answered Apr 15 '14 at 10:12

Zar E Ahmer

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score 0 · Answer 5 · edited Jan 01 '16 at 18:22

0

The third line in Nepster's answer should be

String x =path.substring(pos+1 , path.length());

and not String x =path.substring(pos+1 , path.length()-1); since substring() method takes the end+1 offset as the second parameter.

edited Jan 01 '16 at 18:22

Drew

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answered Jan 01 '16 at 18:10

huskygrad

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looks like an answer to me – Drew Jan 01 '16 at 18:22

Remove string after last occurrence of a character

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