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I am unit testing a class TestMe using EasyMock, and one of its methods (say method(N n)) expects a parameter of type N which has a native method (say nativeMethod()).

class TestMe {
    void method(N n) {
        // Do stuff

        n.nativeMethod();

        // Do more stuff
    }
}

method() needs to invoke N.nativeMethod() at some point, and the problem I'm having is that my Easymock mock object for N is unable to override the native method. I do not own class N but I can refactor TestMe in any way necessary.

I decided to make my own class FakeN extends N which overrides nativeMethod to do nothing:

class FakeN extends N {
    FakeN(int pointer) {
        super(pointer);
    }

    @Override
    public void nativeMethod(Object o) {
        // super.nativeMethod() is an actual native method defined as:
        // public native void nativeMethod(Object o)
        //
        // IGNORE
    }
}

but while the compiler does not complain, when I run the test it appears that N.nativeMethod() is the one being invoked and not FakeNs version.

Is there a workaround here that I can use?

scorpiodawg
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1 Answers1

8

The native methods can be overridden just like any other methods, unless they are declared final. Just be sure that you're calling TestMe.method(N n) with an instance of FakeN.

tibtof
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  • That's what I thought from comments on [this page](http://www.coderanch.com/t/380733/java/java/Overriding-Native-Method-java-io) but it didn't seem to work. I'll go back and check to see if I messed something up. – scorpiodawg Jun 08 '12 at 17:51
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    Turns out that native methods can be overridden by non-native, and vice-versa too. `native` appears to not be a part of the signature. – scorpiodawg May 14 '13 at 23:09