Passing variables in arguments

Question

Im looking how to pass an argument in a find file function this should give all the sh files in my computer first the basename a tab with then all the directories For example myBashfile.sh *sh at the moment i have this: while getopts b opt do case $opt in b) find / -name $OPTARG -printf "%f\n"-print 2>/dev/null ;; esac done wich gives only the output of test1.sh test60.sh anothertest.sh

but i need as output: (with a tab) test1.sh /home/directory5/directory6 test60.sh /home/directory50/directory6 anothertest.sh /home/directory5/directory6

can anyone help me please?

What have you tried? You should read this : http://meta.stackexchange.com/a/128553 — Seki, Jun 08 '12 at 14:16
Tangentially, the shell is going to try to expand `*sh` by looking in your current directory before it is passed to your script. Start with `myBashfile.sh "*sh"` so that your script actually sees the asterisk. — chepner, Jun 08 '12 at 14:40

score 1 · Answer 1 · edited May 23 '17 at 12:03

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A comprehensive answer and the manuals. In brief:

$1 # means the 1st argument
$2 # means the 2nd argument
$@ # means all arguments

edited May 23 '17 at 12:03

Community

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answered Jun 08 '12 at 14:22

Vidul

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Passing variables in arguments

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