Append element as child of Anti-XML element

Question

Suppose I have an XML document stored as an Anti-XML Elem:

val root : Elem =
    <foo attr="val">
        <bar/>
    </foo>

. I want to append <baz>blahblahblah</baz> to the root element as a child, giving

val modified_root : Elem =
    <foo attr="val">
        <bar/>
        <baz>blahblahblah</baz>
    </foo>

For comparison, in Python you can just root.append(foo).

I know I can append (as a sibling) to a Group[Node] using :+, but that's not what I want:

<foo attr="val">
    <bar/>
</foo>
<baz>blahblahblah</baz>

How do I append it as the last child of <foo>? Looking at the documentation I see no obvious way.

Similar to Scala XML Building: Adding children to existing Nodes, except this question is for Anti-XML rather than scala.xml.

score 9 · Accepted Answer · answered Jun 25 '12 at 13:08

Elem is a case class, so you can use copy:

import com.codecommit.antixml._

val root: Elem = <foo attr="val"><bar/></foo>.convert
val child: Elem = <baz>blahblahblah</baz>.convert

val modified: Elem = root.copy(children = root.children :+ child)

The copy method is automatically generated for case classes, and it takes named arguments that allow you to change any individual fields of the original instance.

score 3 · Answer 2 · answered Jun 25 '12 at 16:31

Although not yet relevant, but there is an addChild/ren method on Elem in master in the Anti-XML repo. Its implementation currently contains a bug, but there is an outstanding pull request to fix it. So you should probably use that in a future release.

(Would've made this a comment, but I'm not yet allowed to do so.)

Append element as child of Anti-XML element

2 Answers2