I have a php script by the following address C:\Denwer\home\localhost\www\upload_record_test.php. 
This script shows some text. But if I try to execute this script from the commmand line by command php C:\Denwer\home\localhost\www\upload_record_test, I get the html response with many errors and the message Call to undefined function curl_init(). The code:
<?php
    $_POST_DATA=array();
    $_POST_DATA['id']='AccountPagesView.a_book/45';
    $_POST_DATA['old_value']='1';
    $_POST_DATA['value']='2';
    $ch=curl_init();
    curl_setopt($ch, CURLOPT_URL, 'http://localhost/index.php/welcome/update_record');
    curl_setopt($ch, CURLOPT_POSTFIELDS, $_POST_DATA);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_VERBOSE, 1);
    $real_result=curl_exec($ch);
    $expected_result=array('result'=>'LOGIN', 'old_value'=>'1');
    $real_result=json_decode($real_result, true);
    if (count(array_intersect($real_result, $expected_result))==2)
    {
        echo "THE TEST HAS BEEN COMPLETED";
    }
    else 
    {
        echo "THE TEST HASN'T BEEN COMPLETED<br/>";
        echo "RESULT:";
        print_r($real_result);
        echo "<br/>EXPECTED RESULT:";
        print_r($expected_result);
    }
?>
Please, tell me, how can I execute this script from the command line and get only resulted text? Thanks in advance.