Serving image's data string over HTTPS while URLs on HTTP

Question

I am attempting to read an image file, as a base64 encoded string and output a data string when the connection uses HTTPS/SSL, and otherwise put out the URL in the IMG src attribute if it is only on HTTP. Here is my current code, however it does not work.

<?php 
function base64_encode_image($filename, $filetype) {
    if (($_SERVER["HTTPS"] == "on") && $filename) {
        $file = "/home/content/61/9295861/html/resource/image$filename";
        $imgbinary = fread(fopen($file, "r"), filesize($file));
        return "data:image/$filetype;base64," . base64_encode($imgbinary);
    } else {
        return $filename;
    }
}
?>
<img src="<?php echo base64_encode_image('/resource/image/logo-96x72.png', 'png'); ?>" width="96" height="72" />

It outputs:

<img src="<br />
<b>Warning</b>:  fopen(/home/content/61/9295861/html/resource/image/resource/image/logo-96x72.png) [<a href='function.fopen'>function.fopen</a>]: failed to open stream: No such file or directory in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
<br />
<b>Warning</b>:  filesize() [<a href='function.filesize'>function.filesize</a>]: stat failed for /home/content/61/9295861/html/resource/image/resource/image/logo-96x72.png in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
<br />
<b>Warning</b>:  fread() expects parameter 1 to be resource, boolean given in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
data:image/png;base64," width="96" height="72" />

See this post It might help you. http://stackoverflow.com/questions/3011222/dealing-with-http-content-in-https-pages — Ahsan Khurshid, Jul 31 '12 at 05:33
Any reason you're doing this? embedding images as base64 completely eliminates any chance to cache the images - you wouldn't save anything on bandwidth or ssl/tcp overhead - you'd just increase your bill heavily. — Marc B, Jul 31 '12 at 05:33
also provided the error now, so itll make more sense, my apologies — Solo, Jul 31 '12 at 05:51
why don't you use `$imgbinary = file_get_contents($file);`, also you read mode should be `"rb"` instead of `"r"` — Musa, Jul 31 '12 at 05:51
`/html/resource/image/resource/image/...` is the right path?! — Anirudh Ramanathan, Jul 31 '12 at 06:34

score 1 · Accepted Answer · answered Jul 31 '12 at 05:59

You have added the /image/resource directory twice to your URL which is resulting in a file not found error.

$file = "/home/content/61/9295861/html/resource/image$filename";
$filename = "/resource/image/logo-96x72.png"

So your File URL is /home/content/61/9295861/html/resource/image/resource/image/logo-96x72.png

score 0 · Answer 2 · answered Jul 31 '12 at 06:50

0

Change

<img src="<?php echo base64_encode_image('/resource/image/logo-96x72.png', 'png'); ?>" width="96" height="72" />

to

<img src="<?php echo base64_encode_image('logo-96x72.png', 'png'); ?>" width="96" height="72" />

answered Jul 31 '12 at 06:50

pho

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Serving image's data string over HTTPS while URLs on HTTP

2 Answers2