Go equivalent of PHP's 'implode'

Question

What is the Go equivalent of PHP's 'implode'?

http://stackoverflow.com/tags/go/info – code_martial Aug 23 '12 at 09:43 — code_martial, Aug 23 '12 at 09:43
http://en.wikipedia.org/wiki/Go_%28programming_language%29 – Dmytro Zarezenko Aug 23 '12 at 09:43 — Dmytro Zarezenko, Aug 23 '12 at 09:43

score 70 · Accepted Answer · answered Aug 23 '12 at 09:44

70

In the standard library: strings.Join

func Join(a []string, sep string) string

http://golang.org/pkg/strings/#Join

Cheers!

answered Aug 23 '12 at 09:44

thwd

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Thanks a lot! I spent about half an hour searching for this and stackoverflow got me the answer in less than 5 minutes! OTOH, I now feel a bit dumb to not have browsed through the "strings" package documentation. – code_martial Aug 23 '12 at 09:48

score 13 · Answer 2 · answered Aug 23 '12 at 09:45

13

Join in the strings library. It requires the input array to be strings only (since Go is strongly typed).

Here is an example from the manual:

s := []string{"foo", "bar", "baz"}
fmt.Println(strings.Join(s, ", "))

answered Aug 23 '12 at 09:45

Emil Vikström

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score 7 · Answer 3 · edited Aug 24 '12 at 07:34

7

s := []string{"this", "is", "a", "joined", "string\n"};
strings.Join(s, " ");

Did this help you?

edited Aug 24 '12 at 07:34

Musa

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answered Aug 23 '12 at 09:46

Matti Simperi

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Iveronanomi · Answer 4 · 2018-11-11T05:35:40.593

As i remember, PHP don't have strict typing. Probably not worst idea to use something like this.

package main

import (
    "fmt"
    "strings"
)

func Implode(glue string, args ...interface{}) string {
    data := make([]string, len(args))
    for i, s := range args {
        data[i] = fmt.Sprint(s)
    }
    return strings.Join(data, glue)
}

type S struct {
    z float64
}

func main() {

    v := Implode(", ", 1, "2", "0.2", .1, S{});
    fmt.Println(v)
}

Go equivalent of PHP's 'implode'

4 Answers4