php simple html dom parse img html5 attributes?

Question

How to use simple html dom parse img html5 attribute: data-original

$htmls = '<img class="lazy" alt="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" title="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" data-original="http://www.repubblica.it/images/2012/08/26/130634575-506cc9ae-11b8-4a53-920c-539a3811e46b.jpg" src="http://www.repubblica.it/static/images/homepage/2012/lazy.png" width="130" height="98" style="display: inline; ">';
$html = str_get_html($htmls);
$fata = $html->find('img'); 
foreach($fata as $newimage){
    echo $newimage->data-original; //0
    echo $newimage->src; //http://www.repubblica.it/static/images/homepage/2012/lazy.png
}

I could get the attribute src, but data-original return 0

@Stephen Sarcsam Kamenar, yes, how to get this value use simple html dom? — Giberno, Aug 26 '12 at 15:10

score 27 · Accepted Answer · answered Aug 26 '12 at 15:13

27

$newimage->data-original;

means

$newimage->data - original;

A way round this is to try:

$property = 'data-original';
$newimage->$property;

or, to use the alternative syntax:

$newimage['data-original'];

answered Aug 26 '12 at 15:13

Rich Bradshaw

71,795
44
182
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19

right, in php it should be `$newimage->{'data-original'};`, thanks. – Giberno Aug 26 '12 at 15:24
I realize this is old but I came across this, submitted an edit for this to use the proper syntax on the final line. – Kobi Tate Sep 05 '16 at 05:23
perfect solution, really helped me. – Parmendra Singh Apr 18 '19 at 10:39

score 6 · Answer 2 · answered Oct 25 '14 at 04:59

6

Just an FYI:

I tried:

$newimage['data-original'];

but this is what worked for me:

$property = 'data-original';
$newimage->$property;

answered Oct 25 '14 at 04:59

Chad

643
2
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22

The alternative syntax didn't work for me neither, but the other one did the trick. – Vahid Amiri Feb 12 '16 at 08:24
1

Same, got an error saying I couldn't use a Simple HTML DOM element as an array. Ended up using `$newImage->{'data-original'}` syntax which worked OK. – Luke Stevenson Dec 19 '16 at 02:16

score 0 · Answer 3 · answered May 24 '18 at 04:16

0

Hope this will work

$thumbs= $video->find('img[class=image]', 0)->{data-original};

answered May 24 '18 at 04:16

Annapurna Agarwal

61
3

score 0 · Answer 4 · answered Jan 20 '22 at 12:10

Using braces would be more efficient:

$newimage->{'data-original'};

Another Example:

<?php
   class foo {
     var $bar = 'I am bar.';
     var $arr = array('I am A.', 'I am B.', 'I am C.');
     var $r   = 'I am r.';
   }

   $foo = new foo();
   $bar = 'bar';
   $baz = array('foo', 'bar', 'baz', 'quux');
   echo $foo->$bar . "\n";
   echo $foo->{$baz[1]} . "\n";

   $start = 'b';
   $end   = 'ar';
   echo $foo->{$start . $end} . "\n";

   $arr = 'arr';
   echo $foo->{$arr[1]} . "\n";

?>

Read more about variables wraped in braces: PHP documentation: Variables

php simple html dom parse img html5 attributes?

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