How to eliminate standard output of subprocess.Popen in Python?

Question

When i did something in Python as:

ping = subprocess.Popen("ping -n 1 %s" %ip, stdout=subprocess.PIPE)

it is always to print out to screen:

(subprocess.Popen object at 0x.... )

It's a bit annoying for me. Do you know how to avoid that std output ?

Running `ping = subprocess.Popen(['ping', '127.0.0.1'], stdout=subprocess.PIPE)` produces no output. — Blender, Aug 26 '12 at 22:52
see here [how to ping multiple hosts using subprocess](http://stackoverflow.com/a/12102040/4279) — jfs, Aug 26 '12 at 22:53
I guess you are getting away with calling Popen wrongly because your shell is brain dead — John La Rooy, Aug 26 '12 at 23:25

score 2 · Accepted Answer · answered Aug 27 '12 at 00:15

It looks like you're trying to get the stdout from the process by printing the ping variable in your example. That is incorrect usage of subprocess.Popen objects. In order to correctly use subprocess.Popen this is what you would write:

ping_process = subprocess.Popen(['ping', '-c', '1', ip], stdout=subprocess.PIPE)

# This will block until ping exits
stdout = ping_process.stdout.read()
print stdout

I also changed the arguments you used for ping because -n is an invalid argument on my machines implementation.

How to eliminate standard output of subprocess.Popen in Python?

1 Answers1