I can easily find '\n' in notepad++, but my problem here is that I have to find '\n' when not followed by a specific character ("#" in this case). So do I use Regex with '\n'? Is it possible?
Example :
Stuff to ignore
#Like that
Stuff
To change
I can easily find '\n' in notepad++, but my problem here is that I have to find '\n' when not followed by a specific character ("#" in this case). So do I use Regex with '\n'? Is it possible?
Example :
Stuff to ignore
#Like that
Stuff
To change
Try lookahead assersion:
\n(?!#)
You can find some specifics in this question, but first make sure your line-endings are purely \n.  
Mac OS line-endings are \r (OSX is \n), Windows/DOS are \r\n,and UNIX-style are \n, mostly.  
The regex you are looking for is probably .*\n[^#].*, specifying [^...] (not set)  
But you could try using the EOL regex character, $, instead:
.*$[^#].* 
Or, as xdazz said, just try \n(?!#)