Grep Print Only After Match

Question

I used grep that outputs a list like this

/player/ABc12
/player/ABC321
/player/EGF987
/player/egf751

However I want to only give the name of the players such ABC321, EFG987, etc...

grep only shows you the lines that contain what you found. usually you'd use awk/sed to filter things so you only get the sub-parts of the line. — Marc B, Oct 01 '12 at 23:56

Gilles Quénot · Answer 1 · 2012-10-02T01:25:33.000

24

Start using grep :

$ grep -oP "/player/\K.*" FILE
ABc12
ABC321
EGF987
egf751

Or shorter :

$ grep -oP "[^/]/\K.*" FILE
ABc12
ABC321
EGF987
egf751

Or without -P (pcre) option :

$ grep -o '[^/]\+$' FILE
ABc12
ABC321
EGF987
egf751

Or with pure bash :

$ IFS=/ oIFS=$IFS
$ while read a b c; do echo $c; done < FILE
ABc12
ABC321
EGF987
egf751
$ IFS=$oIFS

edited Oct 02 '12 at 01:25

answered Oct 02 '12 at 00:09

Gilles Quénot

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score 13 · Accepted Answer · answered Oct 02 '12 at 00:31

13

@sputnick has the right idea with grep, and something like that would actually be my preferred solution. I personally immediately thought of a positive lookbehind:

grep -oP '(?<=/player/)\w+' file

But the \K works perfectly fine as well.

An alternative (somewhat shorter) solution is with sed:

sed 's:.*/::' file

answered Oct 02 '12 at 00:31

Tim Pote

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the sed expression worked out better for me – user1709294 Oct 02 '12 at 02:12

score 5 · Answer 3 · answered Oct 02 '12 at 00:05

5

Stop using grep.

$ awk -F/ '$2 == "player" { print $3 }' input.txt
ABc12
ABC321
EGF987
egf751

answered Oct 02 '12 at 00:05

Ignacio Vazquez-Abrams

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score 0 · Answer 4 · answered Oct 02 '12 at 00:30

0

One way using GNU grep and a positive lookbehind:

grep -oP '(?<=^/player/).*' file.txt

Results:

ABc12
ABC321
EGF987
egf751

answered Oct 02 '12 at 00:30

Steve

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Grep Print Only After Match

4 Answers4