Hello I want to get Accurate location so that i have used following link
What is the simplest and most robust way to get the user's current location in Android?
below is the code from that site :
      LocationResult locationResult = new LocationResult(){
    @Override
    public void gotLocation(Location location){
        //Got the location!
    }
   };
MyLocation myLocation = new MyLocation();
myLocation.getLocation(this, locationResult);
Now in LocationResult Class i have modified it and want to show LOCATION's in textview
so i have write below code 
 public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    LocationResult locationResult = new LocationResult(){
        @Override
        public void gotLocation(Location location){
            TextView txtValue = (TextView)findViewById(R.id.txtValue);
            txtValue.setText("LATITUDE : - "+location.getLatitude()+"\n\n LONGITUDE :- "+location.getLongitude()+"\n\n ALTITUDE :- "+location.getAltitude());
        }
    };
    myLocation = new MyLocation();
    myLocation.getLocation(this, locationResult);
}
but in that i am getting exception like
below is my logcat
 10-04 17:06:35.699: E/AndroidRuntime(5733): FATAL EXCEPTION: Timer-0
 10-04 17:06:35.699: E/AndroidRuntime(5733): java.lang.NullPointerException
 10-04 17:06:35.699: E/AndroidRuntime(5733):    at    com.example.gps_accurate_data.MainActivity$1.gotLocation(MainActivity.java:22)
 10-04 17:06:35.699: E/AndroidRuntime(5733):    at com.example.gps_accurate_data.MyLocation$GetLastLocation.run(MyLocation.java:119)
 10-04 17:06:35.699: E/AndroidRuntime(5733):    at java.util.Timer$TimerImpl.run(Timer.java:284)
 
     
     
    