I came across a shell script that contains a statement like,
if [ $val -eq $? ]
What does $? mean here?
I came across a shell script that contains a statement like,
if [ $val -eq $? ]
What does $? mean here?
$?
returns the status of the last finished command. Status 0 tells you that everything finished ok.
In addition the $ sign is a special symbol - and in that case $val extract the value that is hold by the variable val
$# = number of arguments. Answer is 3.
$@ = what parameters were passed. Answer is 1 2 3.
$? = was last command successful. Answer is 0 which means 'yes'.
What does $? mean here?
$? is the last result of an exit-status ... 0 is by default "successfull"
bash# ls *.*
bash# echo $?
bash# 0
bash# ls /tmp/not/existing/
bash# echo $?
bash# 2
This is the value of the exit status of the previous command. This is 0 in case of success.
ls *.* or ls would produce the same result. Meaning show zero or more files with any extension in the current directory.
echo $? would display the exit status. If at least one file is displayed from the last command ,the exit status would be zero(success).