if
double d =  1.999e-4
I want my output to be 0.0001999.
How can I do it?
if
double d =  1.999e-4
I want my output to be 0.0001999.
How can I do it?
 
    
    NumberFormat formatter = new DecimalFormat("###.#####");  
String f = formatter.format(d);  
You can explore the sub classes of NumberFormat class to know more details.
 
    
    I suppose there is a method in BigDecimal Class called toPlainString().
e.g. if the the BigDecimal is 1.23e-8 then the method returns 0.0000000124.
BigDecimal d = new BigDecimal("1.23E-8");
System.out.println(d.toPlainString());
Above code prints 0.0000000123, then you can process the string as per your requirement.
 
    
     
    
    You can do it like this:
    double d = 1.999e-4;
    NumberFormat nf = NumberFormat.getInstance();
    nf.setMinimumFractionDigits(7);
    System.out.println(nf.format(d));
Check out the documentation of NumberFormat's methods to format your double as you see fit.
DecimalFormat is a special case of NumberFormat as its constructor states, I don't think that you need its functionality for your case. Check out their documentation if you are confused. Use the factory method getInstance() of NumberFormat for your convenience.
 
    
    If all you want is to print like that.
System.out.printf("%1$.10f", d);
you can change 10f, 10=number of decimal places you want.
