bit of a jQuery noob but learning quickly thanks to StackOverflow.
Can anyone give me code that will get data from a form and write it out to a cookie (not a session cookie) using jQuery. I am loading the jQuery cookie plugin from here:
https://github.com/carhartl/jquery-cookie
I'd also like to know if I have to load my code when the DOM is ready as previously with php I loaded cookies first thing. Can't get my head round the DOM yet.
Thanks in advance.
OK here is the current code, thanks to reply below. I can't get the cookie working though but the alert works fine when uncommented:
           <form id="myform">
              <fieldset>
                <h3>Search</h3>
                <p>
                  <label>Your search *</label>
                  <input type="text" id="mysearch" pattern="[a-zA-Z ]{5,}" maxlength="30" />
                </p>
                <fieldset>
                    <input type="range" id="range" min="1" max="30" value="10"  />
                    <input type="range" id="range2" min="30" max="9000" value="2000"  />
                 </fieldset>
                <button id="subbtn" type="submit">Submit form</button>
                <button type="reset">Reset</button>
              </fieldset>
            </form>
        $(function() {
        // initialize tooltip
        $(".imgwrap").tooltip({ 
        //$(".tooltip").tooltip({ effect: 'slide'});
           // tweak the position
           offset: [10, 2],
           // use the "slide" effect
           effect: 'slide'
        // add dynamic plugin with optional configuration for bottom edge
        }).dynamic({ bottom: { direction: 'down', bounce: true } });
        });
        //this one loads the form validator
        $("#myform").validator();
        //this one for the slider
        $(":range").rangeinput();
    $("#subbtn").on("click", function () {
    // alert("Cookie!");
        $.cookie('Searchitem', $("#mysearch").val(), { expires: 365 });
    });
Any ideas why my cookie is not setting? Browser is set to accept and I'm debugging with Firebug.
 
     
     
    