Match url with regex but leave specific string from match

Question

I want to match the following URL

/root/folder/123

without the /root in front of it. I was trying around with this pattern ((?!root).)*$ which I found in this answer: https://stackoverflow.com/a/406408/237312

but it doesn't work either, because it still matches oot/folder/123. I thought about something like (?!(root)+.)*$ which matches nothing, so I'm looking for an answer here.

Do you want to match the URL but return everything without `/root` or do you want to match URLs like this if they do **not** start wit `/root`? — Martin Ender, Nov 05 '12 at 10:51
I want to match URLs starting with `/root`in front, but I don't want to match it. Kev's asnwer is exactly what I was looking for. — sascha, Nov 05 '12 at 10:55

score 2 · Accepted Answer · answered Nov 05 '12 at 10:49

2

You can use lookbehind syntax: (?<=...)

For example:

(?<=/root).*$

It'll match /folder/123.

answered Nov 05 '12 at 10:49

kev

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score 1 · Answer 2 · answered Nov 05 '12 at 10:52

1

You could do this:

\/root(.+)

The first group, i.e., $1 will be /folder/123

answered Nov 05 '12 at 10:52

Jiman

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Match url with regex but leave specific string from match

2 Answers2