warning: header information

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Headers already sent by PHP

I am a begginner in php and I want to create an download button but I received an error that i don't understand. This is my error:

"Warning: Cannot modify header information - headers already sent by (output started at D:\Program Files\xampp\htdocs\FormsGenerator\index.php:125) in D:\Program Files\xampp\htdocs\FormsGenerator\download.php on line 11"

On 125 row I had open the tag for php to call the functions created. This is my cod for button functionality:

<?php
class fileDownload{
  function fileDownload(){
      $core_path = dirname(__FILE__);
      $file_path = "{$core_path}/file/form.html";
      $file_info = array(
            'name' => basename($file_path),
            'size' => filesize($file_path)
        );

      header('Content-Type: application/html');
      header('Content-Description: File Transfer');
      header('Content-Disposition: attachment; filename="'.$file_info['name'].'"');
      header('Content-Lenght: '.$file_info['size']);
      $file = fopen($file_path, 'rb');

      while(!feof($file)){
        echo fread($file, 256);
      }

      fclose($file);
      return;
  }
}
?>

And here is the created object that calls the class:

if(isset($_GET['download'])){
       include 'download.php';
        $download = new fileDownload();
}

Can someone help me?

Look for any output being sent before the attachment is being sent to the browser. Also, It seems you have made an error here: `header('Content-Lenght: '.$file_info['size']);` (Should be content-length) — user1909426, Jan 03 '13 at 17:25

score 1 · Accepted Answer · answered Jan 03 '13 at 17:23

1

Before calling header function you cannot send any output to browser, not even from simple HTML code that you have above your php. That must be the reason

answered Jan 03 '13 at 17:23

Hanky Panky

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warning: header information

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