java.net.MalformedURLException: no protocol:

Question

Why I am getting no protocol if i have http in the url path?

Log:

network: Connecting http://xxx.ccc.local/upload/up.php?aa=0&bb=Ap%F3lice+de+Seguro&cc=1028&from=documentos with cookie "CLinkLanguage=en; __utma=232844939.1396040569.1356709687.1357294077.1357902500.12; __utmz=232844939.1356709687.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); __utmb=232844939.24.10.1357902500; symfony=e0lpbkrcu0bidkpiujd1if4pt4; __utmc=232844939; CLinkLanguage=en; PHPSESSID=uv31kr1vpojvqgnc9ae9nda921"

Exception:

    java.net.MalformedURLException: no protocol: 
        at java.net.URL.<init>(Unknown Source)
        at java.net.URL.<init>(Unknown Source)
        at java.net.URL.<init>(Unknown Source)

html

 <APPLET  CODE = "wjhk.jupload.JUploadApplet" ARCHIVE = "upload/wjhk.jupload.jar" WIDTH = "600" HEIGHT = "400" MAYSCRIPT></XMP>
        <PARAM NAME = CODE VALUE = "wjhk.jupload.JUploadApplet" >
        <PARAM NAME = ARCHIVE VALUE = "upload/wjhk.jupload.jar" >
        <PARAM NAME = "type" VALUE="application/x-java-applet;version=1.4">
        <PARAM NAME = "scriptable" VALUE="false">
        <PARAM NAME = "postURL" VALUE ="{$url}">
        <PARAM NAME = "anexosID" VALUE ="{$anexosID}">
        <PARAM NAME = "subanexosID" VALUE ="{$IdConsulta}">
        <PARAM NAME = "companyID" VALUE ="{$companyID}">
        <PARAM NAME = "resultURL" VALUE ="{$resultUrl}">
        <param name="debug" value="true">


    Java 1.4 or higher plugin required.

<APPLET  CODE = "wjhk.jupload.JUploadApplet" ARCHIVE = "upload/wjhk.jupload.jar" WIDTH = "600" HEIGHT = "400" MAYSCRIPT></XMP>
    <PARAM NAME = CODE VALUE = "wjhk.jupload.JUploadApplet" >
    <PARAM NAME = ARCHIVE VALUE = "upload/wjhk.jupload.jar" >
    <PARAM NAME = "type" VALUE="application/x-java-applet;version=1.4">
    <PARAM NAME = "scriptable" VALUE="false">
    <PARAM NAME = "postURL" VALUE ="http://xxx.ccc.local/upload/up.php?aa=0&bb=Alvar%E1%2Ffg&cc=1028&from=documentos">
    <PARAM NAME = "anexosID" VALUE ="">
    <PARAM NAME = "subanexosID" VALUE ="">
    <PARAM NAME = "companyID" VALUE ="">
    <PARAM NAME = "resultURL" VALUE ="">
    <param name="debug" value="true">


Java 1.4 or higher plugin required.
</APPLET>

Show us the code and show us the *exact* value that you pass in to the `URL` constructor. — Joachim Sauer, Jan 11 '13 at 12:36
@Esailija, this is an applet, i don't have access to the source code. — daniel__, Jan 11 '13 at 12:51
@loops how are you giving this to the applet, show the html or javascript source code. The url passed to the URL constructor is an empty string. — Esailija, Jan 11 '13 at 12:52
Are you getting this error..... java.net.MalformedURLException: no protocol: {$VARS['HOST']}/upload/up.php?aa=0&bb=$idConsulta&cc=$COMPANYID&from=$from ........... — Jayamohan, Jan 11 '13 at 12:56
@loops please just show the resulting html source code, not PHP. You can view it from view-source: in a browser. — Esailija, Jan 11 '13 at 13:02
@loops well as you can see, most of the values are empty in the resulting html — Esailija, Jan 11 '13 at 13:06

score 1 · Accepted Answer · edited May 23 '17 at 11:56

The value of the postURL parameter is a URL that can be parsed without exceptions, therefore the problem is somewhere else. What you can do:

Experiment with various applet parameters
Ask for support from the developers of the applet
If you don't have the source code of the applet, you can probably still decompile it, and find out how it works: Where can I find a Java decompiler?

The following program shows only that the postURL value is OK for Java:

public class A {
    public static void main(String[] args) throws MalformedURLException {
        String s = "http://xxx.ccc.local/upload/up.php?aa=0&bb=Alvar%E1%2Ffg&cc=1028&from=documentos";

        URL url = new URL(s);
        String protocol = url.getProtocol();
        System.out.println(String.format("A::main: protocol = '%s'", protocol));
    }
}

java.net.MalformedURLException: no protocol:

1 Answers1