Passing data through intent using Serializable

Question

I've implemented my class with serializable, but it still didn't work.

This is my class:

package com.ursabyte.thumbnail;

import java.io.Serializable;

import android.graphics.Bitmap;

public class Thumbnail implements Serializable {

    private static final long serialVersionUID = 1L;
    private String label = "";
    private Bitmap bitmap;

    public Thumbnail(String label, Bitmap bitmap) {
        this.label = label;
        this.bitmap = bitmap;
    }

    public void set_label(String label) {
        this.label = label;
    }

    public String get_label() {
        return this.label;
    }

    public void set_bitmap(Bitmap bitmap) {
        this.bitmap = bitmap;
    }

    public Bitmap get_bitmap(){
        return this.bitmap;
    }

    //  @Override
    //  public int compareTo(Thumbnail other) {
    //      if(this.label != null)
    //          return this.label.compareTo(other.get_label());
    //      else
    //          throw new IllegalArgumentException();
    //  }

}

This is what I want to be passing.

List<Thumbnail> all_thumbs = new ArrayList<Thumbnail>();
all_thumbs.add(new Thumbnail(string, bitmap));
Intent intent = new Intent(getApplicationContext(), SomeClass.class);
intent.putExtra("value", all_thumbs);

But still it didn't work. I don't know how to use Parcelable, so I use this instead.

`Bitmap` class doesn't implement `Serializable`. You have to use `Parcelable` here. However, it's not a good idea to pass bitmaps using `Parcelable`... — Vladimir Mironov, Jan 15 '13 at 08:25
yes, but be careful with large objects. Intent has a size limit for extras — Vladimir Mironov, Jan 15 '13 at 08:33
or you can add transient before bitmap like this `private transient Bitmap bitmap;` — noone, May 29 '18 at 05:36

score 172 · Answer 1 · edited Nov 22 '15 at 15:00

172

Try to pass the serializable list using Bundle.Serializable:

Bundle bundle = new Bundle();
bundle.putSerializable("value", all_thumbs);
intent.putExtras(bundle);

And in SomeClass Activity get it as:

Intent intent = this.getIntent();
Bundle bundle = intent.getExtras();

List<Thumbnail> thumbs=
               (List<Thumbnail>)bundle.getSerializable("value");

edited Nov 22 '15 at 15:00

Peter Mortensen

30,738
21
105
131

answered Jan 15 '13 at 08:15

ρяσѕρєя K

132,198
53
198
213

2

I got this error : java.lang.RuntimeException: Parcelable encountered IOException writing serializable object (name = com.ursabyte.thumbnail.Thumbnail) – Bias Tegaralaga Jan 15 '13 at 08:25
@tegaralaga : see this example http://www.cnblogs.com/jsonxing/archive/2011/08/17/2143458.html – ρяσѕρєя K Jan 15 '13 at 08:52
The problem is Bitmap class doesn't implement Serializabe like @vmironov said :) – Bias Tegaralaga Jan 16 '13 at 07:57
@tegaralaga : yes i got it then Change Bitmap to image url and convert relevant image in next class instead of passing more bitmaps to other Activity – ρяσѕρєя K Jan 16 '13 at 07:59
@tegaralaga : if this answer help in solving your current issue then mark it as answer.Thanks – ρяσѕρєя K Jan 16 '13 at 08:05
Actually I convert it into byte array. Thanks for your concern, mate :) – Bias Tegaralaga Jan 16 '13 at 09:27
As I understood the following line of your code needs to be changed to: bundle.putSerializable("value", all_thumbs.get(index)); – Ayaz Alifov Feb 23 '15 at 11:03
I had to declare as ArrayList<~>, didn't like just List<~> – hmac Apr 26 '17 at 13:15
@ρяσѕρєяK : How many Serializable Objects can we pass at one time through this bundle ? – Terance Wijesuriya Aug 01 '19 at 06:30

score 15 · Answer 2 · answered Oct 19 '15 at 20:58

This code may help you:

public class EN implements Serializable {
//... you don't need implement any methods when you implements Serializable
}

Putting data. Create new Activity with extra:

EN enumb = new EN();
Intent intent = new Intent(getActivity(), NewActivity.class);
intent.putExtra("en", enumb); //second param is Serializable
startActivity(intent);

Obtaining data from new activity:

public class NewActivity extends Activity {

    private EN en;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        try {
            super.onCreate(savedInstanceState);

            Bundle extras = getIntent().getExtras();
            if (extras != null) {
                en = (EN)getIntent().getSerializableExtra("en"); //Obtaining data 
            }
//...

The object "en" is comming nullable – brunoramonalmeida Aug 20 '16 at 19:17 — brunoramonalmeida, Aug 20 '16 at 19:17

Ayaz Alifov · Answer 3 · 2018-10-15T19:42:44.673

I extended ρяσѕρєя K's answer to make the code full and workable. So, when you finish filling your 'all_thumbs' list, you should put its content one by one into the bundle and then into the intent:

Bundle bundle = new Bundle();

for (int i = 0; i<all_thumbs.size(); i++)
bundle.putSerializable("extras"+i, all_thumbs.get(i));

intent.putExtras(bundle);

In order to get the extras from the intent, you need:

Bundle bundle = new Bundle();
List<Thumbnail> thumbnailObjects = new ArrayList<Thumbnail>();

// collect your Thumbnail objects
for (String key : bundle.keySet()) {
thumbnailObjects.add((Thumbnail) bundle.getSerializable(key));
}

// for example, in order to get a value of the 3-rd object you need to:
String label = thumbnailObjects.get(2).get_label();

Advantage of Serializable is its simplicity. However, I would recommend you to consider using Parcelable method when you need transfer many data, because Parcelable is specifically designed for Android and it is more efficient than Serializable. You can create Parcelable class using:

an online tool - parcelabler
a plugin for Android Studion - Android Parcelable code generator

score 7 · Answer 4 · edited May 06 '19 at 12:53

7

Don't forget to implement Serializable in every class your object will use like a list of objects. Else your app will crash.

Example:

public class City implements Serializable {

private List<House> house;

public List<House> getHouse() {
    return house;
}

public void setHouse(List<House> house) {
    this.house = house;
}}

Then House needs to implements Serializable as so :

public class House implements Serializable {

private String name;

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}}

Then you can use:

Bundle bundle = new Bundle();
bundle.putSerializable("city", city);
intent.putExtras(bundle);

And retreive it with:

Intent intent = this.getIntent();
Bundle bundle = intent.getExtras();
City city =  (City)bundle.getSerializable("city");

edited May 06 '19 at 12:53

Jonathan Hall

75,165
16
143
189

answered May 06 '19 at 08:23

Colyn Tidman

81
1
2

1

This is only part of a solution to a well received question. Can you elaborate please? – harmonica141 May 06 '19 at 08:26
Say you have un object House and you need to Serializable a class City that has a List of houses. You need to implement Serializable in the House class and the City Class – Colyn Tidman May 06 '19 at 08:29
Please improve your answer by including at least a few more words to help explain it. Use the [edit](https://stackoverflow.com/posts/55929627/edit) button instead of adding a comment. [Comments](https://stackoverflow.com/help/privileges/comment) should be used for asking for more information or for suggesting improvements. – Joey May 06 '19 at 08:43

score 6 · Answer 5 · answered Jul 19 '18 at 06:09

Sending Data:

First make your serializable data by implement Serializable to your data class

public class YourDataClass implements Serializable {
String someText="Some text";
}

Then put it into intent

YourDataClass yourDataClass=new YourDataClass();
Intent intent = new Intent(getApplicationContext(),ReceivingActivity.class);
intent.putExtra("value",yourDataClass);
startActivity(intent);

Receiving Data:

YourDataClass yourDataClass=(YourDataClass)getIntent().getSerializableExtra("value");

score 3 · Answer 6 · answered Jan 15 '13 at 08:17

3

Intent intent = new Intent(getApplicationContext(),SomeClass.class);
intent.putExtra("value",all_thumbs);
startActivity(intent);

In SomeClass.java

Bundle b = getIntent().getExtras();
if(b != null)
thumbs = (List<Thumbnail>) b.getSerializable("value");

answered Jan 15 '13 at 08:17

Aditya Kushwaha

839
6
12

score 3 · Answer 7 · answered May 18 '18 at 07:05

In kotlin: Object class implements Serializable:

class MyClass: Serializable {
//members
}

At the point where the object sending:

val fragment = UserDetailFragment()
val bundle = Bundle()
bundle.putSerializable("key", myObject)
fragment.arguments = bundle

At the fragment, where we want to get our object:

val bundle: Bundle? = arguments
    bundle?.let {
        val myObject = it.getSerializable("key") as MyClass
        myObject.memberName?.let { it1 -> showShortToast(it1) }
    }

EvZ · Answer 8 · 2018-03-29T07:29:29.917

2

You need to create a Bundle and then use putSerializable:

List<Thumbnail> all_thumbs = new ArrayList<Thumbnail>();
all_thumbs.add(new Thumbnail(string,bitmap));
Intent intent = new Intent(getApplicationContext(),SomeClass.class);

Bundle extras = new Bundle();

extras.putSerializable("value",all_thumbs);
intent.putExtras(extras);

edited Mar 29 '18 at 07:29

answered Jan 15 '13 at 08:15

EvZ

11,889
4
38
76

score 1 · Answer 9 · edited Mar 13 '18 at 15:11

1

Create your custom object and implement Serializable. Next, you can use intent.putExtra("package.name.example", <your-serializable-object>).

In the second activity, you read it using getIntent().getSerializableExtra("package.name.example")

Otherwise, follow this and this page.

edited Mar 13 '18 at 15:11

Vadim Kotov

8,084
8
48
62

answered Jan 15 '13 at 08:17

Janmejoy

2,721
1
20
38

score 0 · Answer 10 · answered Mar 09 '20 at 09:42

I use the following method when sending a List<MySerializableObject> via intent:

List<Thumbnail> thumbList = new ArrayList<>();
//Populate ...

Intent intent = new Intent(context, OtherClass.class);
intent.putExtra("ThumbArray", thumbList.toArray(new Thumbnail[0]));
//Send intent...

And retrieving it like so:

Thumbnail[] thumbArr = (Thumbnail[]) getIntent().getSerializableExtra("ThumbArray");
if (thumbArr != null) {
    List<Thumbnail> thumbList = Arrays.asList(thumbArr);
}

Aman Shukla · Answer 11 · 2020-04-05T12:54:38.600

0

1- You are using android.graphics.Bitmap which doesn't implements Serializable class so you have to remove that class then it will work.

2- for brief you can visit how to pass data between intents.

edited Apr 05 '20 at 12:54

answered Mar 28 '20 at 04:46

Aman Shukla

37
5

score 0 · Answer 12 · answered Nov 18 '21 at 17:34

If you're here because you did all of this and your app still crashes on switching activities:

My issues lied in my ParentClass using an object of another class in which I forgot to implement Serializable

public class A implements Serializable {
    
        private B[][] b;
    
}

public class B implements Serializable { //forgot this implementation

    B(){
    }

}

score 0 · Answer 13 · answered Mar 17 '22 at 07:30

To pass a list, first implements Serializable in your class.

Then you must cast your list to serializable

val bundle = Bundle();
bundle.putSerializable("list", list as Serializable)

To get list in others activity or fragment

val intent = this.getIntent()
val bundle = intent.getExtras()
val thumbs: List<Thumbnail> = bundle.getSerializable("list") as List<Thumbnail>

Passing data through intent using Serializable

13 Answers13

Linked

Related