is there a way to add characters to a stack?

Question

Is there a way to add characters from a string to a stack without having to create your own push and pop methods?

Examples would be very appreciated!

@us2012 Because it's illegal, you have to use ref type, in this case Character! — Sergii Zagriichuk, Jan 21 '13 at 00:42
How would I successfully attempt to do add characters to a stack? @SergiiZagriichuk — Jay, Jan 21 '13 at 01:44
@Jay answer below, use Stack of Character like this String s = "your string"; Stack d = new Stack(); d.push(s.toCharArray()[0]); // add first symbol from string 'y' — Sergii Zagriichuk, Jan 21 '13 at 02:46

score 8 · Answer 1 · edited May 23 '17 at 12:34

8

Stack<Character> myStack = new Stack<Character>();

char letter = 'a';
myStack.push((Character) letter);

Create a stack that contains Character objects, and cast your chars to Character before you insert them.

Just like ints and Integers, you need to wrap a primitive before you can insert it in to a data structure.

Edit: Apparently Stack is deprecated since it inherits from Vector. Here's why: Why is Java Vector class considered obsolete or deprecated?

As Mark Peters indicated, you should use LinkedList or ArrayDeque.

edited May 23 '17 at 12:34

Community

answered Jan 21 '13 at 00:40

Michael

3

`Stack` is unofficially deprecated in favor of `Deque` implementations, like `LinkedList` and `ArrayDeque`. Unfortunately they messed up by making `Stack` a concrete class and not the name of the interface. – Mark Peters Jan 21 '13 at 00:41
so it isn't possible to accomplish this after all? – Jay Jan 21 '13 at 01:43
BTW, You have no to casting char to Caracters will be autoboxing – Sergii Zagriichuk Jan 21 '13 at 02:53

score 3 · Answer 2 · answered Jan 21 '13 at 02:51

I've decided to answer to this question because there are some misunderstanding... So, There is String:

String s = "your string";

Create Stack or List (LinkedList) look to comment to Answer from Michael

Stack<Character> d = new Stack<Character>();

after all loop with char push logic

 for (char c : s.toCharArray()) {
        d.push(c);
    }

And that is all!!!

2 Answers2