String comparison in Python that is case-insensitive for first letter

Question

I need to match the following string File system full. The problem is Starting F can be lowercase or capital. How can I do this in Python when string comparisons are usually case-sensitive?

Answer 1

I'll be providing boolean indicators for you to play around with (rather than actual if blocks for the sake of conciseness.

Using Regex:

import re
bool(re.match('[F|f]',<your string>)) #if it matched, then it's true.  Else, false.

if the string could be anywhere in your output (I assume string)

import re
bool(re.search('[F|f]ile system full',<your string>))

Other options:

checking for 'f' and 'F'

<your string>[0] in ('f','F')

<your string>.startswith('f') or <your string>.startswith('F')

And there's the previously suggested lower method:

<your string>.lower() == 'f'

Answer 2

You can lower your string before comparing it.

Answer 3

test_string = "File system full"
if "file system full" == test_string.lower():
    # do stuff

Answer 4

>>> s = 'ABC'
>>> s.lower()
'abc'
>>>

After you could use any pattern for matching.

Answer 5

Try converting string into any common(lower or upper) case and then compare

Answer 6

if "File system full".lower() == test_string.lower():
    print True

Answer 7

You can try like this,

>>> import re
>>> bool(re.match('File system full','file system full', re.IGNORECASE))
True

For the more information, re.IGNORECASE

Answer 8

You can use this function
Here,
Both the strings are converted to lowercase using str.lower() ,
If the first letter is the same in both strings, it returns True
otherwise False

def match1(str1 ,str2):
    str1 = str1.lower() # to ignore the case
    str2 = str2.lower()
    if str1[0] == str2[0]:
        return True
    return False

Run on IDLE

>>> mystr = 'File system full'
>>> test1 = 'Flow'
>>> test2 = 'flower'
>>> match1(mystr,test1)
True
>>> match(mystr,test2)
True 

I won't recommend using this technique as
You would need to have both lower and upper-case of the input string's letters
but it works :)

def match2(str1 ,str2):
    if str2[0] == str1[0].lower()\
    or str2[0] == str1[0].upper():
        return True
    return False

Answer 9

You can also do in the below way:

st="File system full"       
vl = re.search(r"(?i)File system full", st)

(?i) matches both uppercase and lower case letters.