Send data from Java(Android) to PHP with POST

Question

I have an app in Android witch takes a picture and needs to upolad it to a server with php.

At first there was no problem, I was able to upload it, but now I need to pass the path where the picture will be uploaded to the server. The problems comes when I try to send two values.

I am using the following code:

private  void httpPostFileUpload(String fpath, String uPath){
        HttpURLConnection connection = null;
        DataOutputStream outputStream = null;
        DataInputStream inputStream = null;

        //Path where to upload
        String uploadPath = uPath;

        String pathToOurFile = fpath;
        Log.v("file path",fpath.toString());
        String urlServer = "http://leojg.alwaysdata.net/tests/androidConnect/handle_upload.php";

        String lineEnd = "\r\n";
        String twoHyphens = "--";
        String boundary =  "*****";
        String fname = "";

        int bytesRead, bytesAvailable, bufferSize;
        byte[] buffer;
        int maxBufferSize = 1*1024*1024;

        try
        {
            File f = new File(pathToOurFile);
            fname =  f.getName();

            FileInputStream fileInputStream = new FileInputStream(f);

            URL url = new URL(urlServer);
            connection = (HttpURLConnection) url.openConnection();

            // Allow Inputs & Outputs
            connection.setDoInput(true);
            connection.setDoOutput(true);
            connection.setUseCaches(false);

            // Enable POST method
            connection.setRequestMethod("POST");

            connection.setRequestProperty("Connection", "Keep-Alive");
            connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

            outputStream = new DataOutputStream( connection.getOutputStream() );
            outputStream.writeBytes(twoHyphens + boundary + lineEnd);

            Log.d("path file", pathToOurFile);
            Log.d("path up", uploadPath);

        outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);
            outputStream.writeBytes(lineEnd);

            bytesAvailable = fileInputStream.available();
            bufferSize = Math.min(bytesAvailable, maxBufferSize);
            buffer = new byte[bufferSize];

            // Read file
            bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0)
            {
                outputStream.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
            }

            outputStream.writeBytes(lineEnd);
            outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // Responses from the server (code and message)
            int serverResponseCode = connection.getResponseCode();
            String serverResponseMessage = connection.getResponseMessage();

            Log.d("amanda", "upload async finished, server response : " + serverResponseMessage);

            fileInputStream.close();
            fileInputStream = null;
            outputStream.flush();
            outputStream.close();
            outputStream = null;
            f= null;



            parent.invokeJs("pictureUploadEnded('" + fname + "')");
            this.delete(fpath);

        }
            catch (Exception ex)
        {
                Log.d("amanda", "exception uploading image : " + ex.getMessage());
        }     
}

I am pretty sure that the problem is in this line

outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile + "\"" + lineEnd);

Which is the one that makes the post body. I dont know where to attrach uploadPath

Check it out... http://stackoverflow.com/questions/2017414/post-multipart-request-with-android-sdk — Mitsuaki Ishimoto, Jan 25 '13 at 00:10

captaindroid · Answer 1 · 2014-09-03T06:02:48.470

Well following Class work for me :

import java.io.DataOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import org.json.JSONException;
import org.json.JSONObject;
import org.json.JSONTokener;
import android.os.Environment;
import android.util.Log;

public class HttpPictureUpload implements Runnable {
private String TAG = "HTTPFILEUPLOAD";
private URL connectURL;
private FileInputStream fileInputStream = null;
private String pictureFileName;
private String myName;

public HttpPictureUpload(String urlString, String pictureFileNameString,
        String myNameString) {
    try {
        connectURL = new URL(urlString);

        pictureFileName = pictureFileNameString;
        myName = myNameString;

    } catch (Exception ex) {
        Log.i(TAG, "URL Malformatted");
    }
}

public void SendPictureNow() {

    Sending();
}

private void Sending() {
    int maxBufferSize = 1 * 1024*1024*1024;
    String lineEnd = "\r\n";
    String twoHyphens = "--";
    String boundary = "*****";

    try {

        fileInputStream = new FileInputStream(Environment
                .getExternalStorageDirectory().toString()
                + "/Picture/"
                + pictureFileName);

        Log.e(TAG, "Starting Http File Sending to URL");

        // Open a HTTP connection to the URL
        HttpURLConnection conn = (HttpURLConnection) connectURL
                .openConnection();
        conn.setChunkedStreamingMode(maxBufferSize);
        // conn.setchu

        // Allow Inputs
        conn.setDoInput(true);

        // Allow Outputs
        conn.setDoOutput(true);

        // Don't use a cached copy.
        conn.setUseCaches(false);

        // Use a post method.
        conn.setRequestMethod("POST");

        conn.setRequestProperty("Connection", "Keep-Alive");

        conn.setRequestProperty("Content-Type",
                "multipart/form-data;boundary=" + boundary);

        DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

        // sending appid
        dos.writeBytes(twoHyphens + boundary + lineEnd);
        dos.writeBytes("Content-Disposition: form-data; name=\"my_name\""
                + lineEnd);
        dos.writeBytes(lineEnd);
        dos.writeBytes(myName);
        dos.writeBytes(lineEnd);
        dos.writeBytes(twoHyphens + boundary + lineEnd);


        dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\""
                + System.currentTimeMillis() + "\"" + lineEnd);
        dos.writeBytes(lineEnd);

        int bytesAvailable = fileInputStream.available();

        byte[] buffer = new byte[bytesAvailable];

        int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

        while (bytesRead > 0) {
            dos.write(buffer, 0, bytesAvailable);
            bytesAvailable = fileInputStream.available();
            bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
            bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
        }
        dos.writeBytes(lineEnd);
        dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

        fileInputStream.close();

        dos.flush();

        Log.e(TAG,
                "File Sent, Response: "
                        + String.valueOf(conn.getResponseCode()));

        InputStream is = conn.getInputStream();

        // retrieve the response from server
        int ch;

        StringBuffer b = new StringBuffer();

        while ((ch = is.read()) != -1) {
            b.append((char) ch);

        }

        String s = b.toString();

        Log.i("Response", s);
        dos.close();
    } catch (MalformedURLException ex) {
        Log.e(TAG, "URL error: " + ex.getMessage(), ex);
    }

    catch (IOException ioe) {
        Log.e(TAG, "IO error: " + ioe.getMessage(), ioe);
    }
}

@Override
public void run() {
    // TODO Auto-generated method stub
}
 }

Above class can be use to send picture file or any other file and one any string.
To use above :

HttpPictureUpload uploadPicture=new HttpPictureUpload("http://serverurl.com/webservice.php", "tux.png", "my name is john");
uploadPicture.SendPictureNow();

Send data from Java(Android) to PHP with POST

1 Answers1