Correct way to handle NumberFormatException

Question

Possible Duplicate:
how to handle number format exception

i want to enter digit in format like $22,000,420 everything is fine but when i erase number it shows number formatting exception.

my xml file is as follows:-

<EditText
        android:id="@+id/editAmountFinanced"
        style="@style/EditTextInputFinance"
        android:layout_below="@+id/txtCreateNewAccount"
        android:layout_centerHorizontal="true"
        android:layout_marginTop="8dp"
        android:ems="10"
        android:hint="AMOUNT FINANCED"
         android:digits="0123456789.,$"
        android:padding="10dp" />

and my android java code is as follows:-

 editAmountFinanced = (EditText)findViewById(R.id.editAmountFinanced);

 editAmountFinanced.addTextChangedListener(new TextWatcher() {

        boolean isEdiging;
        @Override
        public void onTextChanged(CharSequence s, int start, int before,  int count) {
            // TODO Auto-generated method stub

        }

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
            // TODO Auto-generated method stub

        }

        @Override
        public void afterTextChanged(Editable s) {
            // TODO Auto-generated method stub
            if(isEdiging) return;
            isEdiging = true;

            String str = s.toString().replaceAll( "[^\\d]", "" );
            double s1 = Double.parseDouble(str);

            NumberFormat nf2 = NumberFormat.getInstance(Locale.ENGLISH);
            ((DecimalFormat)nf2).applyPattern("$ ###,###.###");
            try {

                s.replace(0, s.length(), nf2.format(s1));

                isEdiging = false;
            } catch(NumberFormatException e) {

            }

        }
    });

thanks

score 2 · Accepted Answer · edited May 23 '17 at 11:55

2

Please search for similar questions before posting a question, Take a look here:Similar Question

in your case just put the try above double s1 =, like this

    double s1 = 0.0;
      try {
           s1 = Double.parseDouble(str);
     } catch(NumberFormatException e) {}
        NumberFormat nf2 = NumberFormat.getInstance(Locale.ENGLISH);
        ((DecimalFormat)nf2).applyPattern("$ ###,###.###");
         s.replace(0, s.length(), nf2.format(s1));

         isEdiging = false;

edited May 23 '17 at 11:55

Community

1
1

answered Feb 04 '13 at 09:41

Mr.Me

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Can you explain what happens exactly ? – Mr.Me Feb 04 '13 at 09:45
But with the try and catch moved around Double.parseDouble the exception should be caught... so it shouldn't be a problem – Mr.Me Feb 04 '13 at 09:51
ya then m not getting any error but i want to enter $ sign and comma – Avinash Kumar Pankaj Feb 04 '13 at 09:55
Adding the above code to your catch clues will fix the problem – Mr.Me Feb 04 '13 at 09:59
thamks..but that didnt help.... :( – Avinash Kumar Pankaj Feb 04 '13 at 10:11
1

Just edited the answer , and tested on my device , working 100% – Mr.Me Feb 04 '13 at 11:32

score 0 · Answer 2 · edited May 23 '17 at 10:24

0

I think you will get answer from the folowing question and answers

NumberFormatException - Android

lang.NumberFormatException in android

edited May 23 '17 at 10:24

Community

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answered Feb 04 '13 at 09:41

Parvathy

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Correct way to handle NumberFormatException

2 Answers2