Find IMG tag and get it's "src" from within a RSS feed node

Question

This may be a very basic question. So please excuse me for the noobness. I'm trying to get myself familiar with xml traversing. Suppose I've this node

[content]
 <img src="some url" />
 <a href="some link">Some link</a>
 Some text after the link.
[/content]

As you can see, the node contains a mixture of text and tags. So I was wondering if I could target the img tag within that node and get it's src attribute?

I'm using simplexml to read the xml file.

If I do just $xml->content, the browser is showing an image, a link and the text. So I was hoping there was some option to "find" the <img> tag within the content node.

UPDATE

Okay. I think I might have used the wrong technical terms. Are RSS feeds are XML one and the same? I'm getting the XML feed from this URL

You are looking for HTML inside CDATA (text) elements of the RSS Feed XML. For the HTML, you find the answer in a duplicate question. For the XML, there are *tons* of duplicate quesitons. Stackoverflow works best asking one question at a time ;) — hakre, Feb 06 '13 at 00:58

score 3 · Accepted Answer · answered Feb 04 '13 at 10:39

3

I got it figured it out myself. What I did was take the entire content of the [content] node and then use preg_match to find the <img> tag from it.

$content = $xml->content;
preg_match('/(<img[^>]+>)/i', $content, $matches);
echo $matches[0];

answered Feb 04 '13 at 10:39

asprin

9,579
12
66
119

score 0 · Answer 2 · answered Feb 04 '13 at 10:03

0

At the moment content is not a XML node. It should be formed like this;

<content></content>

To get the image source just do;

$xml->content->img['src']

Simplexml makes nodes accessible via '->'. Node attributes are accessible via array notation '["attr name"]'

Hope this helps you

answered Feb 04 '13 at 10:03

mvbrakel

936
5
16

Nothing is getting displayed, just blank – asprin Feb 04 '13 at 10:08
Because the source given (feed/entry/content) is partially html entities encoded. – mvbrakel Feb 04 '13 at 10:43

score 0 · Answer 3 · answered Feb 04 '13 at 10:07

This should help you:

<?php

    $html = '
        <body>
            <img src="some url" />
            <a href="some link">Some link</a>
            Some text after the link.
        </body>
    ';

    $xml = simplexml_load_string($html);
    foreach($xml->children() as $child)
    {
        if ($child->getName() === 'img')
        {
            $attributes = $child->attributes();
            $img_source = $attributes['src'];
            echo $img_source;
        }
    }
?>

Apologies. My file does not seem to be an XML. I updated by question content. — asprin, Feb 04 '13 at 10:30

Find IMG tag and get it's "src" from within a RSS feed node

UPDATE

3 Answers3