How to declare variables for another function without passing it as argument of other function?

Question

I want to know how can i do it?

e.g.

function get() {
   alert(s);
}
function declare() {
   var s = "Blah";
   get();
}

But I get that s is not defined.

I know we can do by passing it as argument and also setting it as global variable but how without both of them?

closures ! for the good of mankind – Nishant Jani Feb 11 '13 at 12:06 — Nishant Jani, Feb 11 '13 at 12:06

score 1 · Accepted Answer · answered Feb 11 '13 at 12:06

1

You can use a closure:

function declare() {
   var s = "Blah";
   function get() {
      alert(s);
   }
   get();
}

answered Feb 11 '13 at 12:06

John Zwinck

I know about closures but that `get()` is just assumed function for example. But in my case it is load event. – Muhammad Talha Akbar Feb 11 '13 at 12:08
Well, I think I answered the question that you asked. Maybe you'd like to try a new post with your actual problem? – John Zwinck Feb 11 '13 at 12:10
ahh man got it to work thanks. Didn't realized that it can be done through some mess with closures. – Muhammad Talha Akbar Feb 11 '13 at 12:17
Just to clarify its the scope of the variable that this depends on and more information about that can be found here. http://stackoverflow.com/questions/500431/javascript-variable-scope – Pablo Jomer Feb 11 '13 at 12:20

1 Answers1