I have a Flask server running in standalone mode (using app.run()). But, I don't want any messages in the console, like
127.0.0.1 - - [15/Feb/2013 10:52:22] "GET /index.html HTTP/1.1" 200 -
...
How do I disable verbose mode?
I have a Flask server running in standalone mode (using app.run()). But, I don't want any messages in the console, like
127.0.0.1 - - [15/Feb/2013 10:52:22] "GET /index.html HTTP/1.1" 200 -
...
How do I disable verbose mode?
 
    
    You can set level of the Werkzeug logger to ERROR, in that case only errors are logged:
import logging
log = logging.getLogger('werkzeug')
log.setLevel(logging.ERROR)
Here is a fully working example tested on OSX, Python 2.7.5, Flask 0.10.0:
from flask import Flask
app = Flask(__name__)
import logging
log = logging.getLogger('werkzeug')
log.setLevel(logging.ERROR)
@app.route("/")
def hello():
    return "Hello World!"
if __name__ == "__main__":
    app.run()
 
    
     
    
    This solution provides you a way to get your own prints and stack traces but without information level logs from flask suck as 127.0.0.1 - - [15/Feb/2013 10:52:22] "GET /index.html HTTP/1.1" 200
from flask import Flask
import logging
app = Flask(__name__)
log = logging.getLogger('werkzeug')
log.disabled = True
 
    
    None of the other answers worked correctly for me, but I found a solution based off Peter's comment. Flask apparently no longer uses logging for logging, and has switched to the click package. By overriding click.echo and click.secho I eliminated Flask's startup message from app.run().
import logging
import click
from flask import Flask
app = Flask(__name__)
log = logging.getLogger('werkzeug')
log.setLevel(logging.ERROR)
def secho(text, file=None, nl=None, err=None, color=None, **styles):
    pass
def echo(text, file=None, nl=None, err=None, color=None, **styles):
    pass
click.echo = echo
click.secho = secho
@app.route("/")
def hello():
    return "Hello World!"
if __name__ == "__main__":
    app.run()
Between setting the logging level to ERROR and overriding the click methods with empty functions, all non-error log output should be prevented.
 
    
    To suppress Serving Flask app ...:
os.environ['WERKZEUG_RUN_MAIN'] = 'true'
app.run()
 
    
    In case you are using WSGI server , please set the log to None
gevent_server = gevent.pywsgi.WSGIServer(("0.0.0.0", 8080), app, log=None)
 
    
     
    
    @Drewes solution works most of the time, but in some cases, I still tend to get werkzeug logs. If you really don't want to see any of them, I suggest you disabling it like that.
from flask import Flask
import logging
app = Flask(__name__)
log = logging.getLogger('werkzeug')
log.disabled = True
app.logger.disabled = True
For me it failed when abort(500) was raised.
 
    
    Late answer but I found a way to suppress EACH AND EVERY CONSOLE MESSAGE (including the ones displayed during an abort(...) error).
import os
import logging
logging.getLogger('werkzeug').disabled = True
os.environ['WERKZEUG_RUN_MAIN'] = 'true'
This is basically a combination of the answers given by Slava V and Tom Wojcik
 
    
    Another reason you may want to change the logging output is for tests, and redirect the server logs to a log file.
I couldn't get the suggestion above to work either, it looks like loggers are setup as part of the app starting. I was able to get it working by changing the log levels after starting the app:
... (in setUpClass)
server = Thread(target=lambda: app.run(host=hostname, port=port, threaded=True))
server.daemon = True
server.start()
wait_for_boot(hostname, port)  # curls a health check endpoint
log_names = ['werkzeug']
app_logs = map(lambda logname: logging.getLogger(logname), log_names)
file_handler = logging.FileHandler('log/app.test.log', 'w')
for app_log in app_logs:
    for hdlr in app_log.handlers[:]:  # remove all old handlers
        app_log.removeHandler(hdlr)
    app_log.addHandler(file_handler)
Unfortunately the * Running on localhost:9151 and the first health check is still printed to standard out, but when running lots of tests it cleans up the output a ton.
"So why log_names?", you ask.  In my case there were some extra logs I needed to get rid of.  I was able to find which loggers to add to log_names via:
from flask import Flask
app = Flask(__name__)
import logging
print(logging.Logger.manager.loggerDict)
Side note: It would be nice if there was a flaskapp.getLogger() or something so this was more robust across versions. Any ideas?
Some more key words: flask test log remove stdout output
thanks to:
I spent absolute ages trying to get rid of these response logs with all the different solutions, but as it turns out it wasn't Flask / Werkzeug but Gunicorn access logs dumped on stderr...
The solution was replacing the default access log handler with NullHandler by adding this block in the Gunicorn config file:
logconfig_dict = {
    "version": 1,
    "disable_existing_loggers": False,
    "handlers": {
        "console": {"class": "logging.StreamHandler", "level": "INFO"},
        "null": {"class": "logging.NullHandler"},
    },
    "loggers": {
        "gunicorn.error": {"level": "INFO", "propagate": False, "handlers": ["console"]},
        "gunicorn.access": {"level": "INFO", "propagate": False, "handlers": ["null"]},
    },
}
 
    
    somehow none of the above options, including .disabled = True, worked for me.
The following did the trick though:
logging.getLogger('werkzeug').setLevel(logging.CRITICAL)
Using the latest versions as of November 2021 under Python 3.7.3:
pip3 list | grep -E "(connexion|Flask|Werkzeug)"
connexion2               2.10.0
Flask                    2.0.2
Werkzeug                 2.0.2
 
    
    Here's the answer to disable all logging, including on werkzeug version 2.1.0 and newer:
import flask.cli
flask.cli.show_server_banner = lambda *args: None
import logging
logging.getLogger("werkzeug").disabled = True
 
    
    My current workaround to silence Flask as of 2022-10.
It disables the logging and the startup banner:
class WSServer:
    ...
    @staticmethod
    def _disabled_server_banner(*args, **kwargs):
        """
        Mock for the show_server_banner method to suppress spam to stdout
        """
        pass
    def _run_server(self):
        """
        Winds-up the server.
        """
        # disable general logging
        log = logging.getLogger('werkzeug') 
        log.setLevel(logging.CRITICAL)
        # disable start-up banner
        from flask import cli
        if hasattr(cli, "show_server_banner"):
            cli.show_server_banner = self._disabled_server_banner
        ...
 
    
    I merged custom logs and flask logs so as to provide same log format.
For mote details: https://github.com/senthilkumarimuth/logging_for_python
 
    
    A brute force way to do it if you really don't want anything to log into the console beside print() statements is to logging.basicConfig(level=logging.FATAL). This would disable all logs that are of status under fatal. It would not disable printing but yeah, just a thought :/
EDIT: I realized it would be selfish of me not to put a link to the documentation I used :) https://docs.python.org/3/howto/logging.html#logging-basic-tutorial
The first point: In according to official Flask documentation, you shouldn't run Flask application using app.run(). The best solution is using uwsgi, so you can disable default flask logs using command "--disable-logging"
For example:
uwsgi --socket 0.0.0.0:8001 --disable-logging --protocol=http -w app:app
